[英]How to create a Python timer to count down?
我的代碼:
def timer():
while True:
try:
when_to_stop = 90
except KeyboardInterrupt:
break
except:
print("error, please star game again")
while when_to_stop > 0:
m, s = divmod(when_to_stop, 60)
h, m = divmod(m, 60)
time_left = str(h).zfill(2) + ":" + str(m).zfill(2) + ":" +
str(s).zfill(2) # got cut off, belongs to the line before this
print("time:", time_left + "\r", end="")
if time_left == 0:
print("TIME IS UP!")
time.sleep(1)
when_to_stop -= 1
這工作得很好,除了 time.sleep 意味着我的整個程序都在睡覺,所以在那之后的任何事情都會停止 90 秒。 有什么辦法可以解決這個問題?(或者制作一個沒有時間的新計時器。睡眠?)
我認為,或者,您可以跟蹤計時器的啟動時間,並通過查看經過的時間是否比計時器應該持續的時間長來檢查時間。 我不確定您對 Python 中的類和對象了解多少,但想到的解決方案如下:
import datetime
class Timer:
def __init__(self,**kwargs):
self.start = datetime.datetime.now()
self.length = datetime.timedelta(**kwargs)
self.end = self.start+self.length
def isDone(self):
return (self.end-datetime.datetime.now()).total_seconds()<=0
def timeLeft(self):
return self.end-datetime.datetime.now()
def timeElapsed(self):
return datetime.datetime.now()-self.start
即使你不太了解 class 本身,如果你把它放在你的代碼中,它應該會像一個魅力一樣工作:
#This has the same options as:
#class datetime.timedelta(days, seconds, microseconds, milliseconds, minutes, hours, weeks)
t = Timer(days=2)
while(not t.isDone()):
#Do other game stuff here....
time_left = t.timeLeft()
print(f"time: {time_left}")
#And here....
print("Done now")
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