[英]BigQuery: How to find Scaled Average Weekly Sales?
要解決的場景:我們的最終目標是使用以下公式獲得 Scaled AverageWeeklySales(AWS):
Scaled AWS = (Number of Weeks article has had a record within the store / maximum Number of Weeks in data) * (AWS / Number of Weeks)
輸入'table_a'結構:
Store Article Date Week Year Sales
xx xx xx xx xx xx
嘗試過:構建查詢直到找到 AWS [在商店級別] 並卡在那里繼續進行。 由於我是新手,我不確定如何通過 BigQuery SQL 實現這種 Scaled AWS。需要幫助!
WITH total_weekly_sales AS (
SELECT
Store,
Week,
SUM(Sales) AS TotalWeeklySales
FROM
table_a
GROUP BY
Store,
Week)
SELECT
Store,
AVG(TotalWeeklySales) AS AverageWeeklySales
FROM
total_weekly_sales tws
GROUP BY
Store
樣本數據:
Store Article Date Week Year Sales
11 aa 2019-07-01 202001 2020 4.9
11 bb 2019-07-07 202001 2020 22.5
11 cc 2019-07-08 202002 2020 10.4
12 aa 2019-07-01 202001 2020 5.3
12 bb 2019-07-07 202001 2020 20.2
評論查詢:
Tried Out
”session 中提到的那樣,找到商店級別的 totalweeklysale 並獲得它的平均值給出 AWS]Desired Result: Scaled AWS Formula Part_1 結果 [文章在商店內有記錄的周數/數據中的最大周數]
Store part_1_value
11 1.5 (3/2)
12 1 (2/2)
縮放的 AWS 公式第 2 部分結果 [AWS / 周數]
Store part_2_value
11 18.9 (37.8/2)
12 25.5 (25.5/1)
最終 Output 為: [Part_1 * Part_2]
Store ScaledAverageWeeklySales
11 28.35 (1.5*18.9)
12 25.5 (1*25.5)
總的來說,我們的最終結果應該是 Store Level。 提前致謝!
在您澄清之后,我能夠創建一個查詢來計算您要尋找的內容。
我已經將您提供的數據與WITH語句以及MAX 、 COUNT聚合內置方法一起使用在 BigQuery 中。下面是查詢,
WITH unique_articles AS (
SELECT Store, COUNT(DISTINCT Article) as uniq_art FROM `test-proj-261014.bq_load_codelab.sales_week`
GROUP BY Store
),
max_weeks_st AS (
#not possible to use DATE_DIFF cos the format of the date, the number of weeks would be 1 for the sample data
#so WEEK column will be used instead
SELECT Store, COUNT(Distinct Week) as max_weeks_st FROM `test-proj-261014.bq_load_codelab.sales_week`
group by Store
),
#below returns a struct. So in order to access the int64 value name_of_struct.max_weeks_data
max_weeks_data AS(
SELECT MAX(a.max_weeks_st) AS max_weeks_data FROM max_weeks_st a
),
sum_sales AS (
SELECT Store, SUM(sales) as sum_sales FROM `test-proj-261014.bq_load_codelab.sales_week`
GROUP BY Store
),
final_data AS(
select a.Store, a.uniq_art, b.max_weeks_st,c.sum_sales, max_weeks_data FROM unique_articles a LEFT JOIN sum_sales c USING(Store)
LEFT JOIN max_weeks_st b USING(Store) CROSS JOIN max_weeks_data
)
SELECT Store,((uniq_art/max_weeks_data.max_weeks_data)*(sum_sales/ max_weeks_st)) as AWS_result FROM final_data a
和 output,
Row Store AWS_result
1 11 28.35
2 12 25.5
請注意max_weeks_data是一個struct 。 因此,要訪問其值,必須遵循以下語法: name_of_struct.max_weeks_data 。 此外,請注意,您描述的每個變量都是在臨時表中計算的,始終帶有用於連接表的商店 ID。
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