從嵌套 object 中的鍵或其值獲取父 object

Question

我有一個 object，其中包含有關目錄的文件夾和文件的所有信息以分層方式。
例如

{
  "path": "./parent",
  "name": "parent",
  "type": "folder",
  "children": [
    {
      "path": "./parent/child1",
      "name": "child1",
      "type": "folder",
      "children": [
        {
          "path": "./parent/child1/file1",
          "name": "file1",
          "size": 651956838,
          "extension": ".pdf",
          "type": "file"
        },
        {
          "path": "./parent/child1/file2",
          "name": "file2",
          "size": 468327031,
          "extension": ".pdf",
          "type": "file"
        }
      ]
    },
    {
      "path": "./parent/child2",
      "name": "child2",
      "type": "folder",
      "children": [
        {
          "path": "./parent/child2/file3",
          "name": "file1",
          "size": 651956838,
          "extension": ".pdf",
          "type": "file"
        },
        {
          "path": "./parent/child2/file4",
          "name": "file2",
          "size": 468327031,
          "extension": ".pdf",
          "type": "file"
        }
      ]
    }
  ]
}

現在，我將獲得路徑值，並且我想從這些信息中訪問 children 屬性，該屬性與該路徑的值所在的鍵是同級的。 比如說，我有路徑“./parent/child1”，那么我想要相對於這條路徑的 children 屬性的值，這將是

 [ { "path": "./parent/child1/file1", "name": "file1", "size": 651956838, "extension": ".pdf", "type": "file" }, { "path": "./parent/child1/file2", "name": "file2", "size": 468327031, "extension": ".pdf", "type": "file" } ]

所以我想知道這是否可能。 如果是，那么如何，如果不是，那么還有其他方法可以達到類似的結果嗎？

Answer 1

這可以使用遞歸 function 來完成。

const paths = {
  "path": "./parent",
  "name": "parent",
  "type": "folder",
  "children": [
    {
      "path": "./parent/child1",
      "name": "child1",
      "type": "folder",
      "children": [
        {
          "path": "./parent/child1/file1",
          "name": "file1",
          "size": 651956838,
          "extension": ".pdf",
          "type": "file"
        },
        {
          "path": "./parent/child1/file2",
          "name": "file2",
          "size": 468327031,
          "extension": ".pdf",
          "type": "file"
        }
      ]
    },
    {
      "path": "./parent/child2",
      "name": "child2",
      "type": "folder",
      "children": [
        {
          "path": "./parent/child2/file3",
          "name": "file1",
          "size": 651956838,
          "extension": ".pdf",
          "type": "file"
        },
        {
          "path": "./parent/child2/file4",
          "name": "file2",
          "size": 468327031,
          "extension": ".pdf",
          "type": "file"
        }
      ]
    }
  ]
}

const pathtofind = "./parent/child1";

function findChildrenInPath(object, path) {
    if (path.startsWith(object.path)) {
        if (object.path == path) {
            return object.children;
        }
        else {
            for (let child of object.children) {
                const result = findChildrenInPath(child, path);
                if (result) {
                    return result;
                }
            }
        }
    }
}

const res = findChildrenInPath(paths, pathtofind);
console.log(res);

Answer 2

這是另一種方法，沒有遞歸：

 const data={ "path": "./parent", "name": "parent", "type": "folder", "children": [ { "path": "./parent/child1", "name": "child1", "type": "folder", "children": [ { "path": "./parent/child1/file1", "name": "file1", "size": 651956838, "extension": ".pdf", "type": "file" }, { "path": "./parent/child1/file2", "name": "file2", "size": 468327031, "extension": ".pdf", "type": "file" } ] }, { "path": "./parent/child2", "name": "child2", "type": "folder", "children": [ { "path": "./parent/child2/file3", "name": "file1", "size": 651956838, "extension": ".pdf", "type": "file" }, { "path": "./parent/child2/file4", "name": "file2", "size": 468327031, "extension": ".pdf", "type": "file" } ] } ] }; function getChildrenOf(fs,pth){ let ptha=pth.split('/'); ptha.forEach((d,i,a)=>a[i]=(i?a[i-1]+'/':'')+d); // console.log(ptha); return ptha.filter(d=>d.=="."),reduce((ac)=> a=a.find(d=>d.path===c && d.type==="folder"),children;[fs]). } console,log(getChildrenOf(data.";/parent/child1"));

由於data數組不包含有關當前目錄 ( ./ ) 的任何信息，因此我從ptha數組中刪除了該元素。 否則，搜索將允許在任意深度的文件結構中進行搜索。