[英]Change meta theme-color in dark mode with javascript?
如何將這兩個腳本合並為一個 function,
<script>//<![CDATA[
function LMcheckCheckbox(){
document.querySelectorAll(".checkbox").forEach(function(e) {
"darkmode"===localStorage.getItem("mode")?e.checked=!0:e.checked=!1
})
}
function darkMode(){
localStorage.setItem("mode","darkmode"===localStorage.getItem("mode")?"light":"darkmode"),
"darkmode"===localStorage.getItem("mode")?document.querySelector("body").classList.add("darkmode"):document.querySelector("body").classList.remove("darkmode"),
LMcheckCheckbox()
}
function darkModeHide(){
document.querySelectorAll(".darkmode-switch").forEach(function(e){
e.parentNode.removeChild(e)
})
}
LMcheckCheckbox(),
"undefined"==typeof AzidBloggerSetting
&&(AzidBloggerSetting={tombolDarkmode:!0}),
0==AzidBloggerSetting.tombolDarkmode&&darkModeHide();
//]]>
</script>
這里是更改元主題顏色的腳本
$("meta[name='theme-color']").attr('content', '#333333');
如何將第二個腳本插入第一個腳本? 我想在第一個腳本處於活動狀態時更改元主題顏色。
您需要找到激活暗模式的位置並將您的代碼放在那里。(取消縮小代碼以首先查看發生了什么)
我建議您在開始編寫代碼之前對 javascript 有一個基本的了解!
據我了解,這就是你想要做的:
function LMcheckCheckbox() {
document.querySelectorAll(".checkbox").forEach(function(e) {
"darkmode" === localStorage.getItem("mode") ? e.checked = !0 : e.checked = !1
})
}
function darkMode() {
// this is seemingly where the dark mode is being applyed so :
$("meta[name='theme-color']").attr('content', '#333333');
localStorage.setItem("mode", "darkmode" === localStorage.getItem("mode") ? "light" : "darkmode"), "darkmode" === localStorage.getItem("mode") ? document.querySelector("body").classList.add("darkmode") : document.querySelector("body").classList.remove("darkmode"), LMcheckCheckbox()
}
function darkModeHide() {
document.querySelectorAll(".darkmode-switch").forEach(function(e) {
e.parentNode.removeChild(e)
})
}
LMcheckCheckbox(), "undefined" == typeof AzidBloggerSetting && (AzidBloggerSetting = {
tombolDarkmode: !0
}), 0 == AzidBloggerSetting.tombolDarkmode && darkModeHide();
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