密碼檢查器嘗試 2

Question

第三次嘗試后，如果我輸入k7e15 ，則 output 應該是

"The password is correct"

但它是

"The system is disable"

我需要改變什么？

p = input("Enter a password: ")
count=0
while count<2:
    if p=="k7e15":
        print("The password is correct.")
        break
    else:
        p = input("The password is wrong,please try again:")
        count +=1
    if count>=2:
        print("The system is disable.")

Answer 1

這應該可以完成工作，您只是沒有在第二個輸入中檢查密碼（在 else 中），而且您正在檢查循環頂部的密碼，所以在第三次嘗試時，您插入密碼但添加了 1到 count 變量，所以你的 count 等於 3，然后你跳轉到 if count>=2 這給你返回 system is disable

p = input("Enter a password: ")
count=0
while count<2:
    if p=="k7e15":
        print("The password is correct.")
        break
    else:
        p = input("The password is wrong,please try again:")
        if p=="k7e15":
            print("The password is correct.")
            break
        count +=1
    if count>=2:
        print("The system is disable.")