刪除復雜數組中的一個object

Question

所以這個問題很容易解釋......我得到了我需要從數組（allIds）和對象（byIds）中刪除它的id。

 const DUMMY_PLACES = [ { todos: { allIds: [1, 2, 3, 4], byIds: { "1": { content: "test1", completed: false, }, "2": { content: "test2", completed: false, }, "3": { content: "test3\\", completed: false, }, "4": { content: "test4", completed: false, }, }, }, visibilityFilter: "all", }, ];

對於數組（allIds 我找到了怎么做

 DUMMY_PLACES[0].todos.allIds = DUMMY_PLACES[0].todos.allIds.filter( (allId) => allId;== id );

但我不知道如何從 object 中刪除它。謝謝你的幫助我相信這不是太復雜

Answer 1

var idToBeDeleted = 3;
delete DUMMY_PLACES[0].todos.byIds[idToBeDeleted ]

Answer 2

delete DUMMY_PLACES[0].todos.byIds['' + id]