[英]Upload Files In Folders Using Google Drive API
我目前有以下代碼可以成功地將文件上傳到根目錄中的谷歌驅動器。 我將如何更改以下代碼,以便如果$folderName
存在,它會上傳該文件夾下的文件,但如果$folderName
不存在,它會創建文件夾,將其命名為$folderName
,然后在其下添加文件。
function uploadFiles($filePath, $fileName, $folderName) {
$file = new Google_Service_Drive_DriveFile();
$file->setName($fileName);
$file->setDescription('A test document');
$data = file_get_contents($filePath);
$createdFile = $this->service->files->create($file, array(
'data' => $data,
'uploadType' => 'multipart'
));
}
我相信你的目標和情況如下。
在這種情況下,首先需要確認特定文件夾是否存在。 所以在這種情況下,使用驅動器API中的“文件:列表”的方法。 所以修改后的腳本流程如下。
function uploadFiles($filePath, $fileName, $folderName) {
// 1. Search the existing folder using the folder name.
$res = $this->service->files->listFiles(array("q" => "name='{$folderName}' and trashed=false"));
$folderId = '';
if (count($res->getFiles()) == 0) {
// 2. When the folder of the folder name is NOT existing, the folder is created by the folder name and the folder ID of the created folder is returned.
$file = new Google_Service_Drive_DriveFile();
$file->setName($folderName);
$file->setMimeType('application/vnd.google-apps.folder');
$createdFolder = $this->service->files->create($file);
$folderId = $createdFolder->getId();
} else {
// 3. When the folder of the folder name is existing, the folder ID is returned.
$folderId = $res->getFiles()[0]->getId();
}
// 4. The file is uploaded to the folder using the folder ID.
$file = new Google_Service_Drive_DriveFile();
$file->setName($fileName);
$file->setDescription('A test document');
$file->setParents(array($folderId));
$data = file_get_contents($filePath);
$createdFile = $this->service->files->create($file, array(
'data' => $data,
'uploadType' => 'multipart'
));
}
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