在匹配 python 正則表達式之后查找下一個/上一個字符串

Question

我需要查找文本中提到的人的姓名，我需要使用關鍵字列表過濾所有姓名，例如：

key_words = ["magistrate","officer","attorney","applicant","defendant","plaintfill"...]

For example, in the text:

INPUT: "The magistrate DANIEL SMITH blalblablal, who was in a meeting with the officer MARCO ANTONIO 
and WILL SMITH, defendant of the judgment filed by the plaintiff MARIA FREEMAN "

OUTPUT:
(magistrate, DANIEL SMITH)
(officer, MARCO ANTONIO)
(defendant, WILL SMITH)
(plaintfill, MARIA FREEMAN)

所以我有兩個問題：首先，在鍵之前提到名稱，其次如何構建正則表達式以同時使用所有關鍵字和過濾器。

我嘗試過一些事情：

line = re.split("magistrate",text)[1]
name = []
for key in line.split():
    if key.isupper(): name.append(key)
    else:
        break
" ".join(name)
OUTPUT: 'DANIEL SMITH'

謝謝！

Answer 1

是否必須使用正則表達式？ 如果不是，這就是我的答案，因為我們仍然可以在沒有正則表達式的情況下做到這一點

您可以使用split()方法使用空格分隔符拆分行。 此方法返回一個列表，將其分配給一個變量並遍歷該列表。 嘗試這個

key_words = ["magistrate","officer","attorney","applicant","defendant","plaintfill"]

line = "The magistrate DANIEL SMITH blalblablal, who was in a meeting with the officer MARCO ANTONIO and WILL SMITH, defendant of the judgment filed by the plaintiff MARIA FREEMAN"
line_words = line.split(" ")

for word in line_words:
    if word in key_words:
        Index = line_words.index(word)
        print(word, line_words[Index+1], line_words[Index+2])

Answer 2

我建議將re.findall與兩個捕獲組一起使用，方法如下：

import re
key_words = ["magistrate","officer","attorney","applicant","defendant","plaintiff"]
line = "The magistrate DANIEL SMITH blalblablal, who was in a meeting with the officer MARCO ANTONIO and WILL SMITH, defendant of the judgment filed by the plaintiff MARIA FREEMAN "
found = re.findall('('+'|'.join(key_words)+')'+r'\s+([ A-Z]+[A-Z])',line)
print(found)

Output：

[('magistrate', 'DANIEL SMITH'), ('officer', 'MARCO ANTONIO'), ('plaintiff', 'MARIA FREEMAN')]

說明：在re.findall的模式中使用多個捕獲組（由(和)表示）導致tuple列表（在這種情況下為 2 元組）。 第一個組是通過使用|加入簡單地創建的。 它在模式中像 OR 一樣工作，然后我們有一個或多個空格（ \s+ ），它在任何組之外，因此不會出現在結果中，最后我們有第二組，它由一個或多個空格或 ASCII 大寫字母組成（ [ AZ]+ ) 后跟單個 ASCII 大寫字母 ( [AZ] )，因此它不會捕獲尾隨空格。