[英]Oracle group by issue with sql query
PortfolioNumber LevelCode AccountNumber Status track
123 2 A101 Failed 1
123 2 A102 Failed 1
123 2 A103 Passed 0
123 1 A101 Passed 0
123 1 A102 Passed 0
123 1 A103 Passed 0
123 3 A101 Failed 1
123 3 A102 Failed 1
123 3 A103 Failed 1
456 1 A406 Failed 1
456 1 A407 Passed 0
456 1 A408 Failed 1
我通過對其他幾張表進行某些其他連接來獲得這張表,
此表數據表示什么 - 投資組合編號 (123) 在那里,我們總共有三個 AccountNumber。 我們有不同的 LevelCode(這里是 1,2,3),每個級別都被標記到投資組合編號,並且也將標記相同的 3 個帳號。 並且我們在每一行也有狀態...已創建跟蹤列 jsut 以失敗為 1 並通過為 0,我稍后在下面的查詢中嘗試使用(此列可以刪除)
我試圖找到的 -
每個唯一投資組合編號的最低級別代碼集(包含該集的所有三個accountNumber),其中任一狀態失敗
查詢 - Select PortfolioNumber, LevelCode, min(LevelCode), sum(track) from (table data that I get through some other tables join..pasteed above) group by PortfolioNumber, LevelCode sum(track) > 0'
但這並沒有給出正確的結果和所有列,現在沒有選項了
期望的結果 我是什么
PortfolioNumber LevelCode AccountNumber Status track
123 2 A101 Failed 1
123 2 A102 Failed 1
123 2 A103 Passed 0
456 1 A406 Failed 1
456 1 A407 Passed 0
456 1 A408 Failed 1
使用 Oracle
這個查詢:
select distinct PortfolioNumber,
min(LevelCode) over (partition by PortfolioNumber) LevelCode
from tablename
group by PortfolioNumber, LevelCode
having sum(track) > 0
返回您想要的 PortfolioNumber/LevelCode 組合。
將它與運算符IN
一起使用以獲取表的行:
select *
from tablename
where (PortfolioNumber, LevelCode) in (
select distinct PortfolioNumber,
min(LevelCode) over (partition by PortfolioNumber) LevelCode
from tablename
group by PortfolioNumber, LevelCode
having sum(track) > 0
)
請參閱演示。
結果:
> PORTFOLIONUMBER | LEVELCODE | ACCOUNTNUMBER | STATUS | TRACK
> --------------: | --------: | :------------ | :----- | ----:
> 123 | 2 | A101 | Failed | 1
> 123 | 2 | A102 | Failed | 1
> 123 | 2 | A103 | Passed | 0
> 456 | 1 | A406 | Failed | 1
> 456 | 1 | A407 | Passed | 0
> 456 | 1 | A408 | Failed | 1
我想我只會使用相關的子查詢:
select t.*
from t
where t.levelcode = (select min(t2.levelcode)
from t t2
where t2.portfolionumber = t.portfolionumber and
t2.status = 'Failed'
);
這似乎是最簡單的解決方案,可以通過(portfolionumber, status, levelcode)
上的索引輕松優化。
如果您願意,使用 window 函數的類似方法是:
select t.*
from (select t.*,
min(case when status = 'failed' then levelcode end) over (partition by portfolionumber) as min_failed_levelcode
from t
) t
where levelcode = min_failed_levelcode
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