使用 Django 時出現數據庫錯誤

Question

很高興見到你。 我來自日本，如果我沒有正確使用英語，請教我。 讓我問一些問題。 我創建了一個 django 項目，並在終端嘗試了這段代碼。

python manage.py startapp myhp

然后創建了models.py 文件。 然后我寫了一些 class 並在終端嘗試了這段代碼。

python manage.py startapp runserver

然后出現以下錯誤。（我不知道哪一點很重要，所以我會全部顯示）

Traceback (most recent call last):
  File "C:\ProgramData\Anaconda3\lib\threading.py", line 926, in _bootstrap_inner
    self.run()
  File "C:\ProgramData\Anaconda3\lib\threading.py", line 870, in run
    self._target(*self._args, **self._kwargs)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\utils\autoreload.py", line 53, in wrapper
    fn(*args, **kwargs)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\core\management\commands\runserver.py", line 120, in inner_run
    self.check_migrations()
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\core\management\base.py", line 458, in check_migrations
    executor = MigrationExecutor(connections[DEFAULT_DB_ALIAS])
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\migrations\executor.py", line 18, in __init__
    self.loader = MigrationLoader(self.connection)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\migrations\loader.py", line 49, in __init__
    self.build_graph()
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\migrations\loader.py", line 212, in build_graph
    self.applied_migrations = recorder.applied_migrations()
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\migrations\recorder.py", line 76, in applied_migrations
    if self.has_table():
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\migrations\recorder.py", line 56, in has_table
    return self.Migration._meta.db_table in self.connection.introspection.table_names(self.connection.cursor())
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\backends\base\introspection.py", line 48, in table_names
    return get_names(cursor)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\backends\base\introspection.py", line 43, in get_names
    return sorted(ti.name for ti in self.get_table_list(cursor)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\backends\sqlite3\introspection.py", line 73, in get_table_list
    ORDER BY name""")
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\backends\utils.py", line 100, in execute
    return super().execute(sql, params)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\backends\utils.py", line 68, in execute
    return self._execute_with_wrappers(sql, params, many=False, executor=self._execute)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\backends\utils.py", line 77, in _execute_with_wrappers
    return executor(sql, params, many, context)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\backends\utils.py", line 86, in _execute
    return self.cursor.execute(sql, params)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\utils.py", line 90, in __exit__
    raise dj_exc_value.with_traceback(traceback) from exc_value
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\backends\utils.py", line 84, in _execute
    return self.cursor.execute(sql)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\db\backends\sqlite3\base.py", line 394, in execute
    return Database.Cursor.execute(self, query)
django.db.utils.DatabaseError: file is not a database

我嘗試在同一目錄（hp/myhhp/test.py）中創建以下文件，並且效果很好。

import sqlite3

dbname = 'TEST.db'
conn = sqlite3.connect(dbname)
cur = conn.cursor()

cur.execute('SELECT * FROM persons')

for row in cur:
    print(row)

cur.close()
conn.close()

重點是什么？ 我期待着你的回答。

Answer 1

你不得不說python manage.py runserver ，而不是 python python manage.py startapp runserver :) 這就是你得到錯誤的原因。