如何從另一個列表中刪除空列表？

Question

通過此代碼運行文本后：

import re


def text_manipulator(text):
    paras = re.split('\n|\n ', text)
    item_number = 0
    for item in paras:
        item_replace = re.split('(?<=[.!?]) +', item)
        paras[item_number] = item_replace
        item_number += 1
    fixed_paras = [x for x in paras if x]
    return fixed_paras

我只剩下這個了。

[["Not a postal worker, but I'm good friends with the one on my route,"], [''], ['He has helped me through some tough times (just a nice guy to talk to)'], [''], ['I often offer him a cold gallon of water or a energy drink, he seems to really enjoy.', 'He is a real down to earth guy.']]

我能做些什么不同的事情才能留下這個？：

[["Not a postal worker, but I'm good friends with the one on my route,"], ['He has helped me through some tough times (just a nice guy to talk to)'], ['I often offer him a cold gallon of water or a energy drink, he seems to really enjoy.', 'He is a real down to earth guy.']]

提前致謝

Answer 1

根據any(iterable)的文檔：

如果可迭代的任何元素為真，則返回True 。 如果可迭代對象為空，則返回False 。

因此，當將字符串列表傳遞給Any時，如果列表中的所有元素都是空字符串，那么它將返回False ，因為 Empty String 等效於False 。

因此，在您的代碼中，將倒數第二行替換為：

fixed_paras = [x for x in paras if any(x)]

也會消除帶有空字符串的列表。

注意：此答案基於juanpa.arrivillaga的評論