從 Oracle DB 下載數據並導出到 csv 文件

Question

我連接到某個 Oracle 數據庫並嘗試將數據導出到 csv 文件。 下面是我的 Python 代碼 -

import jpype
import jaydebeapi
import csv

# Assuming I already have established a connection -
# Connection variable is Conn

Curs = Conn.cursor()
Curs.execute("select * from Table")
Data = list(Curs.fetchall())

with open("mycsvfile.csv", "wb") as f:
    w = csv.DictWriter(f, Data[0].keys())
    w.writerow(dict((fn,fn) for fn in Data[0].keys()))
    w.writerows(Data)

但是當我運行上面的代碼時，我得到了錯誤 -

Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
AttributeError: 'tuple' object has no attribute 'keys'

你能幫我找到出路嗎？

非常感謝您的幫助

Answer 1

您可以使用 sqlplus 或 SQLcl 輕松生成 csv：

https://docs.oracle.com/en/database/oracle/oracle-database/12.2/sqpug/generating-HTML-reports-from-SQL-Plus.html

https://oracle-base.com/articles/misc/sqlcl-format-query-results-with-the-set-sqlformat-command

https://www.thatjeffsmith.com/archive/2015/02/a-quick-4-1-trick-set-sqlformat/

Answer 2

我正在使用此代碼使用 Python 創建一個 csv 文件（在我的情況下為 headers ）。 我認為您應該嘗試cx_Oracle ，對我來說，這是從 Python 與 Oracle 數據庫交互的最佳方式。

import os
import sys
import cx_Oracle 

db = cx_Oracle.connect('user/pass@host:port/service_name')
SQL = "select column1 , column2 , .... , columnn from table"
print(SQL)
cursor = db.cursor()
f = open("C:\myfile.csv", "w")
writer = csv.writer(f, lineterminator="\n", quoting=csv.QUOTE_NONNUMERIC)
r = cursor.execute(SQL)

#this takes the column names
col_names = [row[0] for row in cursor.description]

writer.writerow(col_names)

for row in cursor:
   writer.writerow(row)
f.close()