PostgreSQL 左連接查詢與一對多關系

Question

我有下表

CREATE TABLE employee(id serial PRIMARY KEY,employee jsonb);
CREATE TABLE perks_details(id serial PRIMARY KEY,details jsonb);

insert into employee(employee) values
('{"name": "name1", 
   "perks": [
             {"id": 123, "valid_from": "T23:28:56.782Z"}, 
             {"id": 456, "valid_from": "T23:28:56.782Z"}, 
             {"id": 789, "valid_from": "T23:28:56.782Z"}
            ]
  }');

insert into  perks_details(details) values('{"id":123,"detail1":"lorem","detail2":"lorem"}');
insert into  perks_details(details) values('{"id":123,"detail3":"lorem","detail4":"lorem"}');
insert into  perks_details(details) values('{"id":456,"detail5":"lorem","detail6":"lorem"}');

如何使用 perks_details 表中的 id 和聚合函數編寫來自employee左連接perks_details選擇查詢，以便我的結果數據如下所示：

{
  "name": "name1",
  "perks": [
    {
      "id": 123,
      "valid_from": "T23:28:56.782Z",
      "details": [
        {
          "id": 123,
          "detail1": "lorem",
          "detail2": "lorem"
        },
        {
          "id": 123,
          "detail3": "lorem",
          "detail4": "lorem"
        }
      ]
    },
    {
      "id": 456,
      "valid_from": "T23:28:56.782Z",
      "details": [
        {
          "id": 456,
          "detail5": "lorem",
          "detail6": "lorem"
        }
      ]
    },
    {
      "id": 789,
      "valid_from": "T23:28:56.782Z",
      "details": []
    }
  ]
}

我嘗試了多種變體，但無法接近工作查詢。 請在這里給我建議/幫助。

更新我有這個帶有左連接的查詢，但結果不是我所期望的

    select e.id, perk, perks_details.details
      from employee AS e, jsonb_array_elements(employee->'perks') perk
    LEFT JOIN perks_details on perks_details.details -> 'id' = perk->'id'
      group by e.id, perk.value, perks_details.details;

Answer 1

您好，您可以通過以下方式進行操作：

with cte as (
select t1.employee->>'name' "name",
t2.id, t2.valid_from, json_agg(t3.details) "details" 
from employee t1
cross join lateral jsonb_to_recordset(employee->'perks') as t2(id int,valid_from time)
left join perks_details t3 on t2.id::text=t3.details->>'id'
group by 1,2,3
)

select row_to_json(t) from (
select 
name,
json_agg(jsonb_build_object('id',id,'valid_from',valid_from,'details',details)) "perks" 
from cte group by name
) t

演示