過濾數組中的對象值

Question

我已經對對象數組進行了排序：

const arr = [
    {
    "persentage": "30",
    "value": "123"
  },
  {
    "persentage": "27",
    "value": "345"
  },
  {
    "persentage": "2",
    "value": "232"
  },
    {
    "persentage": "2",
    "value": "343"
  },
  {
    "persentage": "9",
    "value": "4334"
  },
    {
    "persentage": "6",
    "value": "43343"
  },
    {
    "persentage": "4",
    "value": "95"
  },
];

如果百分比總和超過 90，我需要按 2 個條件過濾它，我應該跳過其他對象，或者如果對象數大於 6，那么我也應該跳過其余對象。 我有下一個解決方案：

let arr2 = [];

const MAX_PESENTAGE = 90;
const MAX_TOP_VALUES = 6;

let accumulatePersentage = 0;
let countOfValue = 0;

for(const elem of arr) {
  accumulatePersentage += Number(elem.persentage);
  countOfValue++;
  if(accumulatePersentage >= MAX_PESENTAGE || countOfValue > MAX_TOP_VALUES) {
    break;
  }
  arr2.push(elem);
}
  
console.log(arr2)

但我不確定這是最好的解決方案嗎？

Answer 1

你可以像這樣使用reduce ：

 const arr = [ { "persentage": "30", "value": "123" }, { "persentage": "27", "value": "345" }, { "persentage": "2", "value": "232" }, { "persentage": "2", "value": "343" }, { "persentage": "9", "value": "4334" }, { "persentage": "6", "value": "43343" }, { "persentage": "4", "value": "95" } ]; const filtered = arr.reduce((acc, item, i) => { acc.percentage += Number(item.persentage); if (acc.percentage <= 90 && i < 6) { acc.items.push(item); } return acc; }, {percentage: 0, items: []}).items; console.log(filtered);