[英]How to optimize the time of a process in excel VBA MMult
我想為乘法矩陣做一個循環,但我一直被過程的很長時間打斷。
我附上代碼:
Call back_setup_OFF
n_col = 105
dia = 1
Do
dia = dia + 1
Hoja7.Cells(2, n_col) = dia
Hoja7.Cells(105, n_col) = dia
Do
n_row = 106
If Hoja7.Cells(n_row + 103, 5) >= dia Then
J_usar = Hoja7.Cells(n_row + 103, 3)
Else
J_usar = 0
End If
Hoja7.Cells(n_row, n_col) = -Hoja7.Cells(n_row + 103, 2) * Hoja7.Cells(n_row - 103, n_col - 1) - J_usar * Hoja7.Cells(n_row + 103, 4)
n_row = n_row + 1
Loop Until n_row = 206
Hoja7.Range(Hoja7.Cells(3, n_col), Hoja7.Cells(102, n_col)) = Hoja7.Application.WorksheetFunction.MMult(Hoja7.Range("B106:CW205"), Hoja7.Range(Hoja7.Cells(106, n_col), Hoja7.Cells(205, n_col)))
n_col = n_col + 1
Loop Until dia = 100
Call back_setup
和 back_setup 和 back_setup_OFF
Sub back_setup()
Application.Calculation = xlCalculationAutomatic
Application.ScreenUpdating = True
Application.EnableEvents = True
Application.StatusBar = False
End Sub
Sub back_setup_OFF()
Application.Calculation = xlCalculationManual
Application.ScreenUpdating = False
Application.EnableEvents = False
End Sub
問題是 Excel 會在漫長的過程中自行關閉,知道嗎?
每次循環都會重置 n_row ,因此它只會達到 107 ...
Do
n_row = 106 '<<<<<< ???
If Hoja7.Cells(n_row + 103, 5) >= dia Then
J_usar = Hoja7.Cells(n_row + 103, 3)
Else
J_usar = 0
End If
Hoja7.Cells(n_row, n_col) = -Hoja7.Cells(n_row + 103, 2) * Hoja7.Cells(n_row - 103, n_col - 1) - J_usar * Hoja7.Cells(n_row + 103, 4)
n_row = n_row + 1
Loop Until n_row = 206
僅供參考,您有固定的起點/終點和固定增量,但您使用的是Do...Loop
- 您可能應該使用For...Next
循環。
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