[英]EditText crash when empty
所以我有一個 EditText 字段,當用戶點擊一個數字時,它開始倒計時。 當應用程序崩潰時未輸入數字時,問題就開始了。
這就是我試圖做的:
謝謝您的幫助。
public class MainActivity extends AppCompatActivity {
EditText mEnterNumber;
TextView mTest;
int timerIsRunning = 0;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
public void StartRemainder(View view){
mTest = findViewById(R.id.mTest);
mEnterNumber = findViewById(R.id.mEnterNumber);
int userNumb = Integer.parseInt(mEnterNumber.getText().toString()) * 60000;
if(userNumb < 0 || mEnterNumber.toString().isEmpty()){
Toast.makeText(MainActivity.this, "Please enter correct number", Toast.LENGTH_SHORT).show();
}
else{
CountDownTimer userTimer = new CountDownTimer(userNumb,1000) {
@Override
public void onTick(long millisUntilFinished) {
long millis = millisUntilFinished;
//Convert milliseconds into hour,minute and seconds
String hms = String.format("%02d:%02d:%02d",
TimeUnit.MILLISECONDS.toHours(millis),
TimeUnit.MILLISECONDS.toMinutes(millis) - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(millis)), TimeUnit.MILLISECONDS.toSeconds(millis) - TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis)));
mTest.setVisibility(View.VISIBLE);
mTest.setText(hms);
timerIsRunning = 1;
}
@Override
public void onFinish() {
}
}.start();
}
}
----------------------這是我在應用程序崩潰時得到的錯誤:----------------- ---------------
2020-09-04 04:09:15.024 27096-27096/com.example.drinkme E/AndroidRuntime: FATAL EXCEPTION: main
Process: com.example.drinkme, PID: 27096
java.lang.IllegalStateException: Could not execute method for android:onClick
at androidx.appcompat.app.AppCompatViewInflater$DeclaredOnClickListener.onClick(AppCompatViewInflater.java:414)
at android.view.View.performClick(View.java:6256)
at android.view.View$PerformClick.run(View.java:24701)
at android.os.Handler.handleCallback(Handler.java:789)
at android.os.Handler.dispatchMessage(Handler.java:98)
at android.os.Looper.loop(Looper.java:164)
at android.app.ActivityThread.main(ActivityThread.java:6541)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.Zygote$MethodAndArgsCaller.run(Zygote.java:240)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:767)
Caused by: java.lang.reflect.InvocationTargetException
at java.lang.reflect.Method.invoke(Native Method)
at androidx.appcompat.app.AppCompatViewInflater$DeclaredOnClickListener.onClick(AppCompatViewInflater.java:409)
at android.view.View.performClick(View.java:6256)
at android.view.View$PerformClick.run(View.java:24701)
at android.os.Handler.handleCallback(Handler.java:789)
at android.os.Handler.dispatchMessage(Handler.java:98)
at android.os.Looper.loop(Looper.java:164)
at android.app.ActivityThread.main(ActivityThread.java:6541)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.Zygote$MethodAndArgsCaller.run(Zygote.java:240)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:767)
Caused by: java.lang.NumberFormatException: For input string: ""
at java.lang.Integer.parseInt(Integer.java:620)
at java.lang.Integer.parseInt(Integer.java:643)
at com.example.drinkme.MainActivity.StartRemainder(MainActivity.java:40)
at java.lang.reflect.Method.invoke(Native Method)
at androidx.appcompat.app.AppCompatViewInflater$DeclaredOnClickListener.onClick(AppCompatViewInflater.java:409)
at android.view.View.performClick(View.java:6256)
at android.view.View$PerformClick.run(View.java:24701)
at android.os.Handler.handleCallback(Handler.java:789)
at android.os.Handler.dispatchMessage(Handler.java:98)
at android.os.Looper.loop(Looper.java:164)
at android.app.ActivityThread.main(ActivityThread.java:6541)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.Zygote$MethodAndArgsCaller.run(Zygote.java:240)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:767)
錯誤行:
int userNumb = Integer.parseInt(mEnterNumber.getText().toString()) * 60000;
我猜問題出在這一行:
int userNumb = Integer.parseInt(mEnterNumber.getText().toString()) * 60000;
這是因為,與"1"
或"2"
等字符串不同,空字符串( ""
)無法轉換為數字
為了解決這個問題:我們為NumberFormatException
提供了一個try-catch塊
int userNumb = 0;
try {
if (mEnterNumber != null && !TextUtils.isEmpty(mEnterNumber.getText().toString())) {
userNumb = Integer.parseInt(mEnterNumber.getText().toString()) * 60000;
}
}
catch (NumberFormatException ex) {}
在檢查天氣是否為空之前,您沒有從 edittext 中獲取文本。 嘗試這個 :
if(userNumb < 0 && mEnterNumber.`getText()`.toString().isEmpty()){
Toast.makeText(MainActivity.this, "Please enter correct number",
Toast.LENGTH_SHORT).show();
int userNumb = Integer.parseInt(mEnterNumber.getText().toString()) * 60000;
}
如您所見,我已將整數轉換放在 if 塊中,因為這也可能是其原因。
就像 Felix Favor 所說的那樣,這是因為您試圖將非數字項解析為字符串。 這一行:
mEnterNumber = findViewById(R.id.mEnterNumber);
如果不輸入任何內容,很可能會解析為 Null。 您可以嘗試將其設置為數值:
mEnterNumber = findViewById(R.id.mEnterNumber);
if mEnterNumber.getText().toString().equals("")
{
int userNumb = 0; // or whatever value you want to set as a starting default
}
else
{
int userNumb = Integer.parseInt(mEnterNumber.getText().toString()) * 60000;
}
當然,這總是需要更多改進來檢查或防止其他非數字條目。
或者,您也可以像這樣在 XML 中設置它:
<EditText
android:id="@+id/mEnterNumber"
...
android:text="0" />
我使用這樣的東西 -
if (mEnterNumber.getText().toString().matches("")){
Toast.makeText(this, "Please Enter any number", Toast.LENGTH_SHORT).show();
return;
}
我希望這將防止崩潰。
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