[英]Variable declaration in switch-case statements in JavaScript
我創建了一個函數 day_of_week(dayy) 並在函數中使用了 switch-case 語句。
function day_of_week(dayy) {
var result;
switch (dayy) {
case 1:
result = "monday";
case 2:
result = "Tuesday";
case 3:
result = "wednesday";
case 4:
result = "thursday";
case 5:
result = "friday";
case 6:
result = "saturday";
case 7:
result = "sunday";
default:
result = "No day";
}
document.write(result);
}
document.getElementById("switch").innerHTML = day_of_week(1);
document.getElementById("switch").innerHTML = day_of_week(2);
實際上在 switch-case 語句中,如果沒有“中斷”,代碼應該隨機執行。 但是在這里,當我聲明名為 result 的變量並在沒有“中斷”的情況下將 case 值分配給它時。 因此,代碼應該隨機執行所有案例而不會中斷。 但是,這里的變量處於重新聲明值並執行最后一種情況的實例下。 我無法知道我的錯誤是在聲明變量還是使用 switch-case 語句以及所有在函數實例下。 請幫忙...
您的代碼中沒有 break 語句。 我希望這對你有用。
<!DOCTYPE html>
<html>
<head>
<script>
function day_of_week(dayy){
var result;
switch(dayy){
case 1: result = "Monday";
break;
case 2: result = "Tuesday";
break;
case 3: result = "wednesday";
break;
case 4: result = "Thursday";
break;
case 5: result = "Friday";
break;
case 6: result = "Saturday";
break;
case 7: result = "Sunday";
break;
default: result = "No day";
}
document.write(result);
}
document.getElementById("switch").innerHTML = day_of_week(2);
</script>
</head>
<body>
</body>
</html>
我會做這樣的事情來獲得隨機的一天:
function getDay() {
const days = ["monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday"];
return days[Math.floor(Math.random() * 7)];
}
我使用 berak 和 Math 方法重構了這段代碼
function day_of_week(day) {
var result;
switch (day) {
case 1:
result = "monday";
break;
case 2:
result = "Tuesday";
break;
case 3:
result = "wednesday";
break;
case 4:
result = "thursday";
break;
case 5:
result = "friday";
break;
case 6:
result = "saturday";
break;
case 7:
result = "sunday";
break;
default:
result = "No day";
}
document.write(result);
}
document.getElementById("switch").innerHTML = day_of_week(Math.floor( Math.random()*10));
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