[英]Sed: How to replace a string found after a specific pattern is located in a file
[英]SED - Insert saved value after certain pattern when a specific string doesn't exist in the file
我有看起來與此類似的文件:
LET: DimX (2660.0)
LET: DimZ (1050.0)
LET: DimS (0.8)
LET: DREHEN (20)
DIM: X DimX
Z DimZ+0.5
S DimS
REF: X1 FOD-23.24
X2 FOD-23.24
Z1 FOD-24.86
Z2 FOD-24.86
POS: CENT_FUNC 1
QSU 10 QSD 10
TURN_AROUND
就像這樣 -請注意第二個中的 STAINLESS :
LET: DimX (2660.0)
LET: DimZ (1050.0)
LET: DimS (0.7)
LET: DREHEN (20)
DIM: X DimX
Z DimZ+0.5
S DimS
STAINLESS
REF: X1 FOD-23.24
X2 FOD-23.24
Z1 FOD-24.86
Z2 FOD-24.86
POS: CENT_FUNC 1
QSU 10 QSD 10
TURN_AROUND
我想將括號中的值保存在匹配LET: DimS ( XX ) 的行中,並插入一個新行MAT: 'XX Correction ' - 其中 XX 是保存值。 在S DimS 之后
所以這應該是第一個例子的結果:
LET: DimX (2660.0)
LET: DimZ (1050.0)
LET: DimS (0.8)
LET: DREHEN (20)
DIM: X DimX
Z DimZ+0.5
S DimS
MAT: '0.8 correction'
REF: X1 FOD-23.24
X2 FOD-23.24
Z1 FOD-24.86
Z2 FOD-24.86
POS: CENT_FUNC 1
QSU 10 QSD 10
TURN_AROUND
第二個示例的結果應保持原樣,因為它包含 STAINLESS:
LET: DimX (2660.0)
LET: DimZ (1050.0)
LET: DimS (0.7)
LET: DREHEN (20)
DIM: X DimX
Z DimZ+0.5
S DimS
STAINLESS
REF: X1 FOD-23.24
X2 FOD-23.24
Z1 FOD-24.86
Z2 FOD-24.86
POS: CENT_FUNC 1
QSU 10 QSD 10
TURN_AROUND
我試過在 S DimS 模式后添加一行:
sed -i -E '/S DimS/I a \\t MAT: "'"0.8 correction"'"'
但這只是給了我:
LET: DimX (2660.0)
LET: DimZ (1050.0)
LET: DimS (0.8)
LET: DREHEN (20)
DIM: X DimX
Z DimZ+0.5
S DimS
MAT: "0.8 correction"
REF: X1 FOD-23.24
X2 FOD-23.24
Z1 FOD-24.86
Z2 FOD-24.86
POS: CENT_FUNC 1
QSU 10 QSD 10
TURN_AROUND
和:
LET: DimX (2660.0)
LET: DimZ (1050.0)
LET: DimS (0.7)
LET: DREHEN (20)
DIM: X DimX
Z DimZ+0.5
S DimS
MAT: "0.8 correction"
STAINLESS
REF: X1 FOD-23.24
X2 FOD-23.24
Z1 FOD-24.86
Z2 FOD-24.86
POS: CENT_FUNC 1
QSU 10 QSD 10
TURN_AROUND
並且obvioulsy不會將值保存在括號中......
有人可以幫我嗎?
謝謝你。
如果您接受 awk 解決方案,當除了簡單的字符串操作之外還有邏輯要執行時,這通常比 sed 更容易......
# Capture the correction amount
/LET: DimS/ { correction = $3; gsub(/[()]/, "", correction) }
# Get ready to print
$1 == "DIM:" { f = 1 }
# Abort print!!
$1 == "STAINLESS" { f = 0 }
# Now is the time to print the extra line if the flag is still set
NF == 0 && f { printf " MAT: '%s correction'\n", correction; f = 0 }
# Output the original lines of the file
{ print }
測試第一個例子:
$ awk -f a.awk file
LET: DimX (2660.0)
LET: DimZ (1050.0)
LET: DimS (0.8)
LET: DREHEN (20)
DIM: X DimX
Z DimZ+0.5
S DimS
MAT: '0.8 correction'
REF: X1 FOD-23.24
X2 FOD-23.24
Z1 FOD-24.86
Z2 FOD-24.86
POS: CENT_FUNC 1
QSU 10 QSD 10
TURN_AROUND
用你的第二個“STAINLESS”例子試試,你會看到多余的行沒有打印出來。
這可能對你有用(GNU sed):
sed -E ':a;N;$!ba;/STAINLESS/b;
s/^(.*LET:\sDimS\s*\(([^)]*).*\n(\s*)S DimS[^\n]*\n)/\1\3MAT: '\''\2 correction'\''/' file
將整個文件收集到內存中並測試它是否包含單詞STAINLESS
。 如果是這樣,則另當別論:使用模式匹配插入所需的文本。
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