[英]How to get the value of an element located in the parent element by class name
我想使用元素的類名查找位於父元素中的元素的值。
下面是我的代碼,它在與我要查找的元素相同的父級中有一個按鈕,但是當我單擊它時,我得到“未定義”。
$(document).on('click', '.four', function(){ var select = $(this).parents(".parent .two").html(); console.log(select); });
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <div class="parent"> <p class="one"> one </p> <p class="two"> two </p> <p class="three"> three </p> <button class="four"> button one </button> </div> <div class="parent"> <p class="one"> five </p> <p class="two"> six </p> <p class="three"> seven </p> <button class="four"> button two </button> </div>
您正在尋找的類(即.two
)是同一個父級的子級,因此它是兄弟級。 您不需要遍歷parents()
並返回以獲取兄弟姐妹,您可以這樣做:
$(document).on('click', '.four', function(){
var select = $(this).siblings(".two").html();
}
工作示例:
$(document).on('click', '.four', function(){ var select = $(this).siblings(".two").html(); console.log(select); });
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <div class="parent"> <p class="one"> one </p> <p class="two"> two </p> <p class="three"> three </p> <button class="four"> button one </button> </div> <div class="parent"> <p class="one"> five </p> <p class="two"> six </p> <p class="three"> seven </p> <button class="four"> button two </button> </div>
如果您出於某種原因確實需要遍歷父母,那么您可以這樣做 - 首先遍歷父母以獲取您想要的類,然后獲取其children()
類.two
:
$(this).parents(".parent").children(".two").html();
$(document).on('click', '.four', function(){ var select = $(this).parents(".parent").find('.two').html(); console.log(select); });
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <div class="parent"> <p class="one"> one </p> <p class="two"> two </p> <p class="three"> three </p> <button class="four"> button one </button> </div> <div class="parent"> <p class="one"> five </p> <p class="two"> six </p> <p class="three"> seven </p> <button class="four"> button two </button> </div>
嘗試這個:
let parent = document.getElementById('parent'); let childs = parent.childNodes; console.log(childs[1].className)
<div class="parent" id="parent"> <p class="one"> five </p> <p class="two"> six </p> <p class="three"> seven </p> <button class="four"> button two </button> </div>
你可以試試這個
$(document).on('click', '.four', function(){
console.log("clicked")
var select = $(this).parent().find('.two').html();
console.log(select);
});
那 ?
document.querySelectorAll('button.four').forEach(btn=>{ btn.onclick=_=>{ console.log( btn.parentElement.querySelector('.three').textContent ) } })
<div class="parent"> <p class="one"> one </p> <p class="two"> two </p> <p class="three"> three</p> <button class="four"> button one </button> </div> <div class="parent "> <p class="one"> five </p> <p class="two"> six </p> <p class="three"> seven </p> <button class="four"> button two </button> </div>
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