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[英]How to fix incompatible types in this struct/linked-list script?
[英]In C, how to print all the values in struct by using linked-list, while this struct is nested?
我創建了兩個結構體和兩個變量 n1 和 n2,這是下面運行代碼時的結果:
10-nick-90.500000
20-威爾遜-100.500000。
我想要的是:
1.將elemtype變量值放入struct LNODE中。
2.使用printlist(LNDOE* head)打印值。
請幫我。
#include <stdio.h>
#include <stdlib.h>
typedef struct elemtype{
int no;
char* name;
double score;
}elemtype;
typedef struct tagnode{
elemtype data;
struct tagnode* next;
}LNODE;
elemtype* print_elemtype(elemtype* data_to_print){
elemtype* p = data_to_print;
if ( p != NULL){
printf("%d-%s-%lf", p->no,p->name,p->score);
}
printf("\n");
return NULL;
}
void creat_link(LNODE** head, int n, void (*input)(elemtype*)){
LNODE* s;
*head = (LNODE*)malloc(sizeof(LNODE));
(*head)->next = NULL;
for(;n>0;n--){
s = (LNODE*)malloc(sizeof(LNODE));
input(&(s->data));
s->next = (*head)->next;
(*head)->next = s;
}
}
int main()
{
elemtype* n1 = malloc(sizeof(elemtype));
elemtype* n2 = malloc(sizeof(elemtype));
n1->name = "nick";
n1->no = 10;
n1->score = 90.5;
n2->name = "wilson";
n2->no = 20;
n2->score = 100.5;
elemtype** s1,**s2;
s1 = &n1;
s2 = &n2;
print_elemtype(n1);
print_elemtype(n2);
free(n1);
free(n2);
n1 = NULL;
n2 = NULL;
}
使用如下代碼在您的鏈表中爬行:
int main(void)
{
struct_type *list = allocat_struct_type();
struct_type *list_copy = list; // always copy the head of the list when your manipulating the list
while (list_copy != NULL) {
printf("%s", list_copy->text_to_display); // text_to_display must be an str type in this exemple
list_copy = list_copy->next;
}
}
如果您仍然有問題,請精確定位何時何地。
隨意再次問我我希望它可以幫助你我試圖理解你會知道但它非常模糊。
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