為什么我看不到我的項目在 netbeans 中運行？

Question

即使它以前工作過，我也無法讓我的項目正確運行。

import org.apache.commons.lang3.StringUtils;
import java.util.Scanner;
       

public class Main {

    static void bar_graph(int un, int deux, int trois, int quatre, int cinque) { //creates method bar_graph to take 5 integers and, for each integer, return that many asterisk
        
        int[] array = {un, deux, trois, quatre, cinque}; //creates array to hold the integers from bar_graph
        String graph = "*"; //creates string equal to *
        
        int counter = 0; //creates integer counter
        
        while(counter < 5){ //beginning of while loop which goes through the five integers in bar_graph and prints out, for each integer, that many asterisk
        String repeated = StringUtils.repeat(graph, array[counter]); //repeats the string graph as many times as the integer at array[counter] and equals it to a string called repeated
        System.out.println(repeated); //string repeated is printed
        counter++; //the counter increases by one
        }
    }
    
    public static void main(String[] args) {
        
        System.out.println("Emma Wilson - Programming Project 3 Exercise 4.16");
        
        Scanner graph = new Scanner(System.in);
        System.out.println("Please enter five integers between 1 and 30: "); //asks user to input five integers between 1 and 30
        
        int first = graph.nextInt(); //creates int first and equals it to first integer the user enters here
        while (first > 30 || first < 1){ //checks that the integer the user entered is between 1 and 30 and asks the user to enter an integer between 1 and 30 over and over
            System.out.println("That is not an integer between 1 and 30. Please enter an integer between 1 and 30: ");
            first = graph.nextInt();
        }
        
        int second = graph.nextInt(); //creates int second and equals it to next integer the user enters here
        while (second > 30 || second < 1){ //checks that the integer the user entered is between 1 and 30 and asks the user to enter an integer between 1 and 30 over and over
            System.out.println("That is not an integer between 1 and 30. Please enter an integer between 1 and 30: ");
            second = graph.nextInt();
        }
        
        int third = graph.nextInt(); //creates int third and equals it to next integer the user enters here
        while (third > 30 || third < 1){ //checks that the integer the user entered is between 1 and 30 and asks the user to enter an integer between 1 and 30 over and over
            System.out.println("That is not an integer between 1 and 30. Please enter an integer between 1 and 30: ");
            third = graph.nextInt();
        }
        
        int fourth = graph.nextInt(); //creates int fourth and equals it to next integer the user enters here
        while (fourth > 30 || fourth < 1){ //checks that the integer the user entered is between 1 and 30 and asks the user to enter an integer between 1 and 30 over and over
            System.out.println("That is not an integer between 1 and 30. Please enter an integer between 1 and 30: ");
            fourth = graph.nextInt();
        }
        
        int fifth = graph.nextInt(); //creates int fifth and equals it to next integer the user enters here
        while (fifth > 30 || fifth < 1){ 
            System.out.println("That is not an integer between 1 and 30. Please enter an integer between 1 and 30: ");
            fifth = graph.nextInt();
        }
        bar_graph(first, second, third, fourth, fifth); //calls method bar_graph
        
        
         
         
         }
}

代碼截圖1：

代碼截圖2：

代碼運行截圖3：

當我運行它時，netbeans 不顯示我輸入的整數或任何輸出。

Netbeans 運行我正確編譯的另一個程序，但不是這個程序。

Answer 1

您嘗試運行一個文件，但運行的是最后一個文件而不是當前文件。

當使用main方法打開多個項目或有多個文件並在 Netbeans 中按“運行”（或按 F6 運行）時，會發生這種情況，它會運行您運行的最后一個文件。

將其視為“運行我上次運行的程序”之類的鍵。

如果要運行另一個文件，只需使用main方法打開文件，右鍵單擊代碼中的每個位置並按“運行文件”（或只需按快捷鍵 shift + F6）。

通過這種方式，您將告訴 Netbeans 不要運行我的最后一個代碼，而是運行這個代碼。

從現在開始，使用 IDE 頂部的“運行”鍵，運行此文件。 除非您對其他文件執行相同操作。