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[英]How can i wait for Ajax GET call response from Node.js and then return true for the droppable to accept dropping?
[英]How can I make code wait for the return of an API call - Node.js
我正在嘗試編寫一個函數來調用 API 並等待 API 返回一個值,我該如何改進我的代碼來做到這一點。 目前它只返回 Promise-pending。
async function getData(options){
const result = new Promise((resolve, reject) => {
request(options, function(error, response) {
if (error) return reject(error);
return resolve(JSON.parse(response.body));
});
});
var fromapi = await result;
return fromapi;
};
嘗試這個
const request = require('request')
function makeRequest(uri, options) {
return new Promise((resolve, reject) => {
return request(uri, options, function (error, response) {
if (error) reject(error);
resolve(response.body);
});
});
}
async function getData(options) {
const result = await makeRequest('https://google.com', options)
console.log(result)
}
getData().then(() => {
}).catch((e) => {
console.log(e)
})
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