正則表達式：從字符串中刪除 's？

Question

字符串輸入： Python's Programming: is very easy to learn

預期輸出： Python Programming: is very easy to learn

這是我到目前為止不起作用的內容：

import re
mystr = "Python's Programming: is very easy to learn"
reg = r'\w+'
print(re.findall(reg, mystr))

如何從python's刪除's ？

Answer 1

您提取一個或多個字母數字字符的所有匹配項。

用

\b's\b

見證明。

說明：

--------------------------------------------------------------------------------
  \b                       the boundary between a word char (\w) and
                           something that is not a word char
--------------------------------------------------------------------------------
  's                       '\'s'
--------------------------------------------------------------------------------
  \b                       the boundary between a word char (\w) and
                           something that is not a word char

蟒蛇代碼：

import re
mystr = "Python's Programming: is very easy to learn"
print(re.sub(r"\b's\b", '', mystr))

Answer 2

這里有兩個選項。 第一個使用正則表達式，第二個使用字符串replace方法。

import re
mystr = "Python's Programming: is very easy to learn"
reg = r"'s"
print(re.sub(reg, '', mystr))
   # prints: Python Programming: is very easy to learn
print(mystr.replace("'s",''))
   # prints: Python Programming: is very easy to learn