我如何將這兩個類鏈接在一起以顯示 Person 和 Address 之間的一對多關系

Question

地址類：

public class Address {

    private String country;
    private String county;
    private String city;
    private String postcode;
    private String HouseNumber;

    public Address(String country, String county, String city, String postcode, String HouseNumber) {
        this.country = country;
        this.county = county;
        this.city = city;
        this.postcode = postcode;
        this.HouseNumber = HouseNumber;
    }

    public void view_adress() {
        String[] address = {country, county, city, postcode, HouseNumber};
        
        for (int i = 0; i<address.length; i++) {
            System.out.println(address[i]);
        }
    }
                
    public void viewHouseNumber() {
        System.out.print(HouseNumber);
    }
}

人物類：

public class Person {
    private String firstName;
    private String lastName;
    private String Date_of_birth;
    private String PhoneNumber;
    private String[] address;
    
    public Person (String firstName, String lastName, String Date_of_birth, String PhoneNumber, String[] address) {
        this.firstName = firstName;
        this.lastName = lastName;
        this.Date_of_birth = Date_of_birth;
        this.PhoneNumber = PhoneNumber;
        this.address = address;
    }

    public void view_PhoneNumber() {
        System.out.print(PhoneNumber);
    }
}

Answer 1

使用 OOP組合。

public class Person {
    //...
    List<Address> addresses;
    //...
}

Person一個實例將具有 0 個或多個Address實例。

請注意，在實際場景中，您最好還希望在Address類中保留一系列userId ，因為多個用戶可能擁有一個或多個地址，這意味着，那你的關系必須是Many-To-Many 。

同樣（完全）重要的是堅持Java 命名約定和名稱：

• 使用PascalCase類；
• 字段和方法名稱使用camelCase命名法；
• ALL_CAPS_SEPARATED_WITH_UNDERSCORES常量。