我正在看 Mike Dane 關於 Guessing Game 的 Python 教程，但我對代碼感到困惑

Question

我對帶有變量 out_of_guesses 的猜謎游戲感到困惑。 而guess != guess_number 而不是(out_of_guesses)。 因為如果使用 NOT 運算符，out_of_guesses 變量將變為 True，因此：雖然guess 不等於秘密數字並且不為 False 繼續？ 所以 out_of_guesses 變量會變為 True 而你會輸？

secret_word = "giraffe"
guess_count = 0
guess_limit = 3
guess = ""
out_of_guesses = False
while guess != secret_word and not (out_of_guesses):
    if guess_count < guess_limit:
        guess = input("Enter guess: ")
        guess_count += 1
    else:
        out_of_guesses = True
if out_of_guesses:
    print("Out of guesses, you lose.")
else:
    print("You win!")

Answer 1

我對帶有變量 out_of_guesses 的猜謎游戲感到困惑。 而guess != guess_number 而不是(out_of_guesses)。 因為如果使用 NOT 運算符，out_of_guesses 變量將變為 True，因此：雖然guess 不等於秘密數字並且不為 False 繼續？ 所以 out_of_guesses 變量會變為 True 而你會輸？

secret_word = "giraffe"
guess_count = 0
guess_limit = 3
guess = ""
out_of_guesses = False
while guess != secret_word and not (out_of_guesses):
    if guess_count < guess_limit:
        guess = input("Enter guess: ")
        guess_count += 1
    else:
        out_of_guesses = True
if out_of_guesses:
    print("Out of guesses, you lose.")
else:
    print("You win!")

Answer 2

我對帶有變量 out_of_guesses 的猜謎游戲感到困惑。 而guess != guess_number 而不是(out_of_guesses)。 因為如果使用 NOT 運算符，out_of_guesses 變量將變為 True，因此：雖然guess 不等於秘密數字並且不為 False 繼續？ 所以 out_of_guesses 變量會變為 True 而你會輸？

secret_word = "giraffe"
guess_count = 0
guess_limit = 3
guess = ""
out_of_guesses = False
while guess != secret_word and not (out_of_guesses):
    if guess_count < guess_limit:
        guess = input("Enter guess: ")
        guess_count += 1
    else:
        out_of_guesses = True
if out_of_guesses:
    print("Out of guesses, you lose.")
else:
    print("You win!")