[英]Dropdown menu toggle rotate arrow
我有兩個隱藏的下拉菜單。 一旦用戶單擊其中之一,它們就會顯示出來。 當一個下拉菜單打開時,它會關閉另一個。 到目前為止,這項工作非常好。 我在每個菜單中添加了一個 SVG 插入符號,當用戶單擊菜單時,它會向下旋轉(90 度)。
當另一個菜單打開時,如何將其旋轉回其初始位置(-360 度)。
var dropdown = document.getElementsByClassName("dropdown-btn");
var i;
for (i = 0; i < dropdown.length; i++) {
dropdown[i].addEventListener("click", function() {
var dropdownContent = this.nextElementSibling;
Array.from(document.querySelectorAll('.dropdown-container')).forEach(el => {
if (el !== dropdownContent)
el.style.display = 'none';
/* if its possible rotate it back here, i couldnt access the carets here */
});
if (dropdownContent.style.display === "block")
dropdownContent.style.display = "none";
else
dropdownContent.style.display = "block";
});
}
.dropdown-btn {
border: none;
background: none;
cursor: pointer;
outline: none;
text-transform: uppercase;
font-family: LinetoCircular;
display: block;
padding-left: 20px;
z-index: 0;
}
#wrapper {
display: flex;
}
/* hidden by default, make the content shifts under the title */
.dropdown-container {
display: none;
font-size: 18px;
padding-top: 10px;
background-color: #575757;
}
.dropdown-container a {
color: white;
padding-left: 30px;
}
.dropdown-container a:hover {
background-color: #414141;
}
<div>
<button class="dropdown-btn">
<div id="wrapper">
<div>Client</div>
<div id="rotate1" class="transformButton" style="position: relative; left: 104px; top: 2px;"><!--this is the caret, may not be visible because its local--></div>
</div>
</button>
<div class="dropdown-container">
<a href="client_properties/" style="height: 30px;"><span style="font-size: 24px;">+</span>Add new</a><br>
<a href=''>first element</a><br>
<a href=''>second element</a><br>
</div>
<div>
<button class="dropdown-btn">
<div id="wrapper">
<div>Car</div>
<div id="rotate2" class="transformButton" style="position: relative; left: 104px; top: 2px;"><!--this is the caret, may not be visible because its local--> </div>
</div>
</button>
</div>
<div class="dropdown-container">
<a href="client_properties/" style="height: 30px;"><span style="font-size: 24px;">+</span>Add new</a><br>
<a href=''>first element</a><br>
<a href=''>second element</a><br>
</div>
</div>
插入符號在這里不可見,但我為它寫了。 它應該緊挨着每個下拉菜單。 現場演示: https : //jsfiddle.net/2mwr4y68/
所有你需要的是
class="dropdown"
.is-open
const dropdowns = document.querySelectorAll(".dropdown"); dropdowns.forEach(el => { const button = el.querySelector(".dropdown-btn"); button.addEventListener("click", () => { // Close all [...dropdowns].filter(x => x != el).forEach(el => el.classList.remove("is-open")); // Toggle one el.classList.toggle("is-open"); }); });
/*QuickReset*/ * {margin:0; box-sizing:border-box;font:14px/1.4 sans-serif;} .dropdown-btn { border: none; background: none; cursor: pointer; outline: none; text-transform: uppercase; font-family: inherit; display: block; } .dropdown-btn::before { display: inline-block; content: "\\25BC"; transition: transform 0.3s; } .dropdown-container { display: none; padding: 10px; background-color: #575757; } .dropdown.is-open .dropdown-btn:before { transform: rotate(180deg); } .dropdown.is-open .dropdown-container { display: block; } .dropdown-container a { color: white; display: block; } .dropdown-container a:hover { background-color: #414141; }
<div class="dropdown"> <button class="dropdown-btn">Client</button> <div class="dropdown-container"> <a href="client_properties/"><span>+</span>Add new</a> <a href=''>first element</a> <a href=''>second element</a> </div> </div> <div class="dropdown"> <button class="dropdown-btn">Car</button> <div class="dropdown-container"> <a href="client_properties/"><span>+</span>Add new</a> <a href=''>first element</a> <a href=''>second element</a> </div> </div>
上述內容不適用於.dropdown
多個集合組
如果是這種情況,請將上述內容包裝起來以說明.dropdown
組
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