如何添加到 INSERT INTO PRIMARY KEY 和 FOREIGN KEY

Question

所以我有兩個表：locations 和雇員我希望locations_id在employees.locations_id是相同的，我試圖在一個語句中全部做到這一點，錯誤是這樣你的SQL 語法有錯誤； 檢查與您的 MySQL 服務器版本相對應的手冊，了解在第 1 行的 'INSERT INTO 員工（employees_id，locations_id）VALUES('e1598','')' 附近使用的正確語法

String sql = " INSERT INTO locations( locations_id , username, password, id, type_of_id, first_name, last_name, phone, email, date_of_birth, address, sex ) VALUES (?,?,?,?,?,?,?,?,?,?,?,?)"
 **Error here --->**           + "INSERT INTO employees(employees_id,locations_id) VALUES (?,SELECT locations_id FROM locations INNER JOIN employees ON locations.locations_id =employees.locations_id)";
    try {

       MicroModelGUI micro = new MicroModelGUI();
        PreparedStatement consulta =  micro.connection.prepareStatement(sql);
         consulta.setString(1, tflid.getText());
         consulta.setString(2, tfuser.getText());
         consulta.setString(3, tfpass.getText());
         consulta.setString(4, tfid.getText());
         consulta.setString(5, tftoid.getText());
         consulta.setString(6, tffirst.getText());
         consulta.setString(7,tflast.getText());
         consulta.setString(8,tfphone.getText());
         consulta.setString(9,tfemail.getText());
         consulta.setString(10,tffdn.getText());
         consulta.setString(11,tfaddress.getText());
         consulta.setString(12,tfsex.getText());
         consulta.setString(13,tfeid.getText());
         int resultado = consulta.executeUpdate();
    

Answer 1

您應該使用INSERT INTO ... SELECT在此處INSERT INTO ... SELECT ：

INSERT INTO employees (employees_id, locations_id)
SELECT ?, l.locations_id
FROM locations l
INNER JOIN employees e ON l.locations_id = e.locations_id;

到? 占位符，您將從 Java 代碼中綁定一個值。 請注意，雖然您的 SQL 版本可能支持將標量子查詢放入VALUES子句中，但您的確切版本很可能會導致錯誤，因為它會返回多行。