[英]How to update state (array of objects) with incoming object in Redux?
例如,當前狀態是:
{
data: [
{id: 1, number: 100},
{id: 2, number: 200},
{id: 3, number: 300}
]
}
行動是:
const action = (id, number) => {
return {id: id, number: number}
}
如何實現滿足以下要求的reducer:
情況1:
//incoming object
{id: 4, number: 400}
//result
{
data: [
{id: 1, number: 100},
{id: 2, number: 200},
{id: 3, number: 300},
{id: 4, number: 400}
]
}
案例2:
//another incoming object
{id: 2, number: 250}
//result
{
data: [
{id: 1, number: 100},
{id: 2, number: 250},
{id: 3, number: 300},
{id: 4, number: 400}
]
}
也許它有一個簡單的解決方案,但我找不到解決這個問題的正確方法:) 另外我想知道在這種情況下的最佳實踐是什么。
先感謝您
我將您的操作更改為使用payload
屬性,但如果您願意,可以將其刪除。 (擁有它更合適)
const reducer = (state, action) => { switch(action.type) { case 'UPDATE_OR_INSERT': return { data: [ ...state.data.filter(x => x.id !== action.payload.id), action.payload, ] } default: } return state; } console.log( reducer({ data: [ {id: 1, number: 100}, {id: 2, number: 200}, {id: 3, number: 300}, {id: 4, number: 400} ] }, { type: 'UPDATE_OR_INSERT', payload: {id: 2, number: 250}}));
您如何看待這個解決方案?
const testState = {
data: []
}
export default (state = testState, action) => {
switch(action.type){
case "SET_DATA":
return [
...state.data.filter(d => d.id !== action.payload.id),
action.payload,
];
default:
return state;
}
};
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