如何過濾對象javascript中的數組值？

Question

我有包含數組的對象，我想根據數組值過濾對象。

例如：

    {
       "sun":["sleep","walk"],
       "mon":["read","dance","ride"],
       "tue":["work","dance","sleep"],
    }

如果我輸入關鍵字“sleep”，那么結果應該如下

    {
      "sun":["sleep"],
      "tue":["sleep"],
    }

任何建議都會有所幫助

Answer 1

解決這個問題的有用工具：

• 對象條目
• Object.fromEntries
• Array.prototype.includes
• 數組.prototype.map
• 數組.prototype.filter

 let obj = { "sun": ["sleep", "walk"], "mon": ["read", "dance", "ride"], "tue": ["work", "dance", "sleep"], }; let result = Object.fromEntries( Object.entries(obj) .filter(kvp => kvp[1].includes('sleep')) .map(([k, v]) => [k, v.filter(o => o === 'sleep')]) ) console.log(result)

Answer 2

只需遍歷對象並進行操作，請在下面找到工作代碼：

 const obj = { "sun": ["sleep", 'walk'], "mon": ["read", "dance", "ride"], "tue": ["work", "dance", "sleep"], } function filterIt(filterString) { const result = {}; for (const prop in obj) { if (obj[prop].includes(filterString)) { result[prop] = [filterString]; } } return result; } const finalResult = filterIt('sleep'); console.log(finalResult);

Answer 3

使用Object.keys 、 map 、 includes 。

let obj ={
       "sun":["sleep","walk"],
       "mon":["read","dance","ride"],
       "tue":["work","dance","sleep"],
    }

let new_obj = {}
let search = 'sleep'

Object.keys(obj).map(key => {
     obj[key].includes(search) ? new_obj[key]=[search] : ''
})

console.log(new_obj)

Answer 4

您可以使用_.transform()創建一個新對象。 檢查值數組 ( v ) 是否包含str ，以及它是否使用包含 str 的新數組分配鍵：

 const fn = (obj, str) => _.transform(obj, (o, v, k) => { if(v.includes(str)) o[k] = [str] }) const obj = { "sun":["sleep","walk"], "mon":["read","dance","ride"], "tue":["work","dance","sleep"], } const result = fn(obj, 'sleep') console.log(result)

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