[英]How to get session_id when using Crawlera lua script in Scrapy Splash?
[英]How to get a correct session_id? (Scrapy, Python)
有一個網址: https : //maps.leicester.gov.uk/map/Aurora.svc/run? inspect_query = QPPRN & inspect_value = ROH9385 & script =% 5CAurora%5Cw3%5CPLANNING%5Cw3PlanApp_MG.AuroraScript%24 & nocache56- f73ee- 87e7-42e82982370f&resize=總是
它返回坐標。 要獲取坐標 - 它執行 3 個請求(我假設):
我在第二步得到 session_id,但這是錯誤的。 我無法使用它在步驟 3 中獲取坐標。 我怎么知道問題出在 session_id 上? 當我插入從瀏覽器獲取的 session_id 時 - 我的代碼工作正常並且接收到坐標。
以下是瀏覽器的正確響應:
這就是我用我的代碼得到的:
這是我的代碼(用於 Scrapy 框架):
''' 導入 inline_requests
@inline_requests.inline_requests
def get_map_data(self, response):
""" Getting map data. """
map_referer = ("https://maps.leicester.gov.uk/map/Aurora.svc/run?inspect_query=QPPRN&"
"inspect_value=ROH9385&script=%5CAurora%5Cw3%5CPLANNING%5Cw3PlanApp_MG.AuroraScript"
"%24&nocache=f73eee56-45da-f708-87e7-42e82982370f&resize=always")
response = yield scrapy.Request(
url=map_referer,
meta=response.meta,
method='GET',
dont_filter=True,
)
time_str = str(int(time.time()*1000))
headers = {
'Referer': response.url,
'Accept': 'application/javascript, */*; q=0.8',
'Accept-Encoding': 'gzip, deflate',
'Accept-Language': 'ru-RU,ru;q=0.9,en-US;q=0.8,en;q=0.7',
'Host': 'maps.leicester.gov.uk',
'Sec-Fetch-Dest': 'script',
'Sec-Fetch-Mode': 'no-cors',
'Sec-Fetch-Site': 'same-origin',
'Connection': 'keep-alive',
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/84.0.4147.135 Safari/537.36'
}
response.meta['handle_httpstatus_all'] = True
url = ( 'https://maps.leicester.gov.uk/map/Aurora.svc/RequestSession?userName=inguest'
'&password=&script=%5CAurora%5Cw3%5CPLANNING%5Cw3PlanApp_MG.AuroraScript%24&'
f'callback=_jqjsp&_{time_str}=' )
reqest_session_response = yield scrapy.Request(
url=url,
meta=response.meta,
method='GET',
headers=headers,
dont_filter=True,
)
session_id = re.search(r'"SessionId":"([^"]+)', reqest_session_response.text)
session_id = session_id.group(1) if session_id else None
print(8888888888888)
print(session_id)
# session_id = '954f04e2-e52c-4dd9-9046-f3f013d3f633'
# pprn = item.get('other', {}).get('PPRN')
pprn = 'ROH9385' # hard coded for the current page
if session_id and pprn:
time_str = str(int(time.time()*1000))
url = ('https://maps.leicester.gov.uk/map/Aurora.svc/FindValue'
f'Location?sessionId={session_id}&value={pprn}&query=QPPRN&callback=_jqjsp'
f'&_{time_str}=')
coords_response = yield scrapy.Request(
url = url,
method='GET',
meta=reqest_session_response.meta,
dont_filter = True,
)
print(coords_response.text)
breakpoint()'''
你能更正我的代碼以便它可以得到坐標嗎?
該網站首先創建一個 sessionId,然后使用 sessionId 在服務器上創建一個層(我猜)。 然后就可以開始請求了,不然就找不到那個sessionId下的地圖圖層了。
import requests
url = "https://maps.leicester.gov.uk/map/Aurora.svc/RequestSession?userName=inguest&password=&script=%5CAurora%5Cw3%5CPLANNING%5Cw3PlanApp_MG.AuroraScript%24"
res = requests.get(url, verify=False).json()
sid = res["Session"]["SessionId"]
url = f"https://maps.leicester.gov.uk/map/Aurora.svc/OpenScriptMap?sessionId={sid}"
res = requests.get(url, verify=False)
url = f"https://maps.leicester.gov.uk/map/Aurora.svc/FindValueLocation?sessionId={sid}&value=ROH9385&query=QPPRN"
res = requests.get(url, verify=False).json()
print(res)
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