如何檢查列表的字典是否為空？

Question

這個想法是檢查 dict 中的列表中的以下 dict 是否為空。

例如，下面的字典

expected_false={"all_dict": [{"A": [1], "B": [], "C": [], "D": []}]}

應該返回空為假，因為鍵 'A' 的值為 1。

而以下內容應返回空為真

expected_empty={"all_dict": [{"A": [], "B": [], "C": [], "D": []}]}

我嘗試了以下代碼，但它給出的與我的想法不同。

all(not d for d in expected_true['all_dict'][0])

Answer 1

any(len(item) for item in expected_true['all_dict'][0].values())

Answer 2

這應該有效：

print(not any(len(expected_false['all_dict'][x]) > 0 for x in expected_false['all_dict']))

Answer 3

字典是一組鍵值對。 偽代碼：

-Get value of 'all_dict' key inside of dictionary that named {expected_false}
-That 'all_dict' key has a value which is a list that contains only one item (which is an another dictionary)
-To address list item : ['all_dict'][0] (we reached first list item, which is a dictionary)
-Use dict.values() method to get all values of keys innermost dictionary
-And each of these values are also list by itself

expected_false['all_dict'][0].values()

因此上面的代碼返回列表。 並檢查每個列表中是否有任何項目。 然后打印結果。

expected_false={"all_dict": [{"A": [1], "B": [], "C": [], "D": []}]}
for item in expected_false['all_dict'][0].values():
    if len(item)!=0:
        a=any(item)
        print(a)