創建以變量為文件名的文本文件

Question

我正在嘗試創建一個新的文本文件，其中一個變量被指定為文件名； 將今天的日期添加到創建的每個文件中。 雖然繼續收到相同的錯誤 -

FileNotFoundError: [Errno 2] No such file or directory: 'TestFileWrite_10/11/2020.txt'

我試過這些方法都沒有成功-

使用 str-

today = date.today()
filename = "TestFileWrite_" + today.strftime("%d/%m/%Y")
f = open(str(filename)+'.txt', "w")
f.write(output1)
# output1 var is referenced within another part of the script.
f.close()

使用 ％-

today = date.today()
filename = "TestFileWrite_" + today.strftime("%d/%m/%Y")
f = open("%s.txt" % filename, "w")
f.write(output1)
# output1 var is referenced within another part of the script.
f.close()

使用 .format-

today = date.today()
filename = "TestFileWrite" + str(today.strftime("%d/%m/%Y"))
f = open("{}.txt".format(filename), "w")
f.write(output1)
# output1 var is referenced within another part of the script.
f.close()

Answer 1

您必須刪除或替換斜杠：

filename = "TestFileWrite_" + today.strftime("%d/%m/%Y")

應更改日期格式，例如：

filename = "TestFileWrite_" + today.strftime("%Y%m%d")

或者

filename = "TestFileWrite_" + today.strftime("%d_%m_%Y")

而且，'filename' 的類型已經是 'str'，所以不需要使用 str() 函數：

f = open(filename+'.txt', 'w')