[英]Add record in detail in master-detail ADF in two sessions
如果我有一個主實體:
@Entity
public class Test implements Serializable {
@Id
@Column(name="TEST_ID" nullable = false)
private BigDecimal testId;
@Column(unique = true, length = 30)
private String code;
@Temporal(TemporalType.TIMESTAMP)
@Column(nullable = false, length = 50)
private String name;
@Column(name="SYS_VERSION_NUMBER",nullable = false, length = 50)
private Long sysVersionNumber;
@OneToMany(mappedBy = "test", orphanRemoval=true, cascade = { CascadeType.PERSIST, CascadeType.MERGE })
private List<TestDetail> testDetailList;
public Test() {}
public String getCode() {
return code;
}
public void setCode(String code) {
this.code = code;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public BigDecimal getTestId() {
return testId;
}
public void setTestId(BigDecimal testId) {
this.testId = testId;
}
public Long getSysVersionNumber() {
return sysVersionNumber;
}
public void setSysVersionNumber(Long sysVersionNumber) {
this.sysVersionNumber = sysVersionNumber;
}
public List<TestDetail> getTestDetailList() {
return testDetailList;
}
public void setTestDetailList(List<TestDetail> testDetailList) {
this.testDetailList = testDetailList;
}
public TestDetail addTestDetailList(TestDetail testDetail) {
getTestDetailList().add(testDetail testDetail);
testDetail.setTest(this);
testDetail.setTestId(this.getTestId());
return testDetail;
}
public TestDetail removeProvbilling(TestDetail testDetail) {
getTestDetailList().remove(testDetail testDetail);
testDetail.setTest(null);
testDetail.setTestId(null);
return testDetail;
}
@Override
public boolean equals(Object object) {
if (this == object) {
return true;
}
if (!(object instanceof Test)) {
return false;
}
final Test other = (Test) object;
if (!(id == null ? other.testId == null : testId.equals(other.testId))) {
return false;
}
return true;
}
@Override
public int hashCode() {
final int PRIME = 37;
int result = 1;
result = PRIME * result + ((test == null) ? 0 : test.hashCode());
return result;
}
}
我有一個細節實體
@Entity
public class Testdetail implements Serializable {
@Id
@Column(name = "TESTDETAIL_ID", nullable = false)
private BigDecimal testdetailId;
@Version
@Column(name = "SYS_VERSION_NUMBER")
private Long sysVersionNumber;
@ManyToOne
@JoinColumn(name = "TEST_ID", insertable=false, updatable=false)
private TEST test;
@Column(name = "TEST_ID",)
private BigDecimal testId;
@Column
private String name;
public Testdetail() {
}
public Test getTest() {
return test;
}
public void setTest(Test test) {
this.test = test;
}
public void setTestId(BigDecimal testId) {
this.testId = testId;
}
public BigDecimal getTestId() {
return testId;
}
public String getName(){
return name;
}
public void setName(String name){
this.name = name;
}
public Long getSysVersionNumber() {
return sysVersionNumber;
}
public void setSysVersionNumber(Long sysVersionNumber) {
this.sysVersionNumber = sysVersionNumber;
}
}
如果我在具有相同測試記錄的兩個選項卡中兩次運行頁面,並在第一個選項卡中為“testDetail”添加新記錄,然后在第二個選項卡中為“testDetail”添加記錄(我在調用em 的sessionbean 中調用方法mergeTest() 。合並(測試)保存),即使 sysversionnumber 正常工作以防止用戶編輯在第二個選項卡中編輯的現有記錄,在第一個選項卡中添加的記錄也消失了。
有沒有辦法阻止用戶在第二個選項卡中添加記錄或鎖定主記錄(如果它是通過 sessionBean 中的 EntityManager 使用的)?
我在調用em.merge(test);
后找到了解決方案em.merge(test);
我必須使用em.lock(test, LockModeType.OPTIMISTIC_FORCE_INCREMENT);
鎖定它em.lock(test, LockModeType.OPTIMISTIC_FORCE_INCREMENT);
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