GUI-Tkinter-Python 程序

Question

如何創建一個按鈕來打開一個打印所有記錄的新窗口。 在程序的以下部分中，我無法在新窗口中打印記錄，但它會在已創建的窗口中打印並且新窗口保持為空。 這是程序的一小部分：-

    root = Tk()
    def query():
      query = Tk()
      query.title('Records')
      query.iconbitmap(r'C:\Users\pankaj\Downloads\Elegantthemes-Beautiful-Flat-Document.ico')
      query.geometry("450x350")

    #Create a database or connect to one
    conn = sqlite3.connect('Payslip.db')
    # Create cursor
    c = conn.cursor()
    #Query the database
    c.execute("SELECT *,oid from Payslip")
    records = c.fetchall()
    #print(records)# to print in the background

    #Loop the results
    print_records = ''
    for record in records: #to show the records
      print_records += str(record[0]) +"\t" + str(record[8])+ "\n"# \t to give space(tab) between them
    query_label = Label(root, text=print_records)
    query_label.grid(row=14, column=0, columnspan=2)

    #Commit Change
    conn.commit()
    # Close Connection
    conn.close()  
  
  #create a Query button
  query_btn = Button(root, text="Show Records", command=query)
  query_btn.grid(row=9,column=0, columnspan=2, pady=10, padx=10, ipadx=135)

Answer 1

那么，你要打印在query_label，您分配到根窗口print_records：

查詢標簽 = 標簽（根，文本=print_records）

你說你創建了一個新窗口，但我在代碼中看不到它，所以你可能想要做這樣的事情：

def query():
    top1 = Toplevel() # creates new window called top1
    print_records = ''
    for record in records: #to show the records
        print_records += str(record[0]) +"\t" + str(record[8])+ "\n"
    query_label = Label(top1, text=print_records) # now the query_label is assigned to top1
    query_label.grid(row=14, column=0, columnspan=2)

但是你想這樣做：

query_label = Label( NEW_WINDOW , text=print_records)