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[英]getting the difference between two rows and perform mathematical operation on the difference mysql
[英]mathematical operation between two select statements
我目前正在嘗試在我的 postgres 數據庫中找到一定數量的預注冊用戶的百分比,操作將是(1185 * 100) / 3104 = 38.17
。 為此,我使用了兩個 select 語句來檢索每個計數,但我一直無法在它們之間進行操作:
+ count +
- 1185 -
- 3104 -
這就是我所擁有的:
select
count(*)
from crm_user_preregistred
left join crm_player on crm_user_preregistred."document" = crm_player."document"
left join crm_user on crm_player.user_id = crm_user.id
where crm_user.email is not null
union all
select
count(*)
from crm_user_preregistred
在此先感謝您的任何提示或幫助。
你可以使用一些 with 子句來簡化你的選擇,用你的 count(*) 選擇替換值,也許對結果進行一些格式化,並檢查 value2 上的 0
with temp_value1 as (
select 1185 as value1 ),
temp_value2 as (
select 3104 as value2 )
select (select temp_value1.value1::float * 100 from temp_value1) /
(select temp_value2.value2::float from temp_value2)
結果:38.17654639175258
與您的選擇:
with temp_value1 as (
select
count(*) as value1
from crm_user_preregistred
left join crm_player on crm_user_preregistred."document" = crm_player."document"
left join crm_user on crm_player.user_id = crm_user.id
where crm_user.email is not null
),
temp_value2 as (
select
count(*) as value2
from crm_user_preregistred
)
select (select temp_value1.value1::float * 100 from temp_value1) / (select temp_value2.value2::float from temp_value2)
您可以在一個查詢中執行此操作:
select count(*) filter (where cu.email is not null) * 100.0 / max(cup.cnt)
from (select cup.*, count(*) over () as cnt
from crm_user_preregistred cup
) cup left join
crm_player cp
on cup."document" = cp."document" left join
crm_user cu
on cp.user_id = cu.id
where cu.email is not null;
我懷疑可以進一步簡化查詢,但是在不了解您的數據模型的情況下,很難提出具體建議。
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