簡體   English   中英

如何消除並行 std::transform_reduce() 的中間容器?

[英]How to eliminate intermediate container for parallel std::transform_reduce()?

通常,我必須找到Sum( f(i), 1, N )Product( f(i), 1, N ) ,其中f(i)在計算上是 CPU 密集型的,而積分 i 來自順序范圍但很大.

使用 C++20 編譯器,我可以編寫 function:

uint64_t solution(uint64_t N)
{
    std::vector<uint64_t> v(N);
    std::iota(v.begin(), v.end(), 1ULL);

    return std::transform_reduce(
                std::execution::par, 
                v.cbegin(), v.cend(), 
                0ull, 
                std::plus<>(), 
                []f(const uint64_t& i)->uint64_t {
                   uint64_t result(0);
                   // expensive computation of result=f(i) goes here
                   // ...
                   return result;
                 });  

}

但這將受到 RAM 的限制。

如何在運行時僅使用 C++20 STL (即沒有特定於供應商的庫或第 3 方庫)完全消除中間 memory 操作與輸入向量,但仍具有高效的並行執行?

免責聲明:我之前沒有實現迭代器或 C++20 的經驗

這似乎對我有用 gcc 10.1 和-std=c++2a 我在很短的時間內把它放在一起,沒有花太多心思,所以實現肯定可以改進,如果只是通過模板化它。 如果將operator<=>替換為舊的雙向比較運算符,這也應該與 C++17 一起運行,但我還沒有測試過。 如果您發現任何錯誤或易於糾正的設計缺陷,歡迎您在下面發表評論,以便改進此答案。

#include <cstddef>

#if __cplusplus > 201703L
#include <compare>
#endif

#include <execution>
#include <iostream>
#include <iterator>
#include <numeric>

class counting_iterator {
public:
  typedef std::ptrdiff_t difference_type;
  typedef std::ptrdiff_t value_type;
  typedef void pointer;
  typedef void reference;
  typedef std::random_access_iterator_tag iterator_category;

private:
  value_type val_{0};

public:
  counting_iterator() = default;
  explicit counting_iterator(value_type init) noexcept : val_{init} {}
  value_type operator*() const noexcept { return val_; }
  value_type operator[](difference_type index) const noexcept {
    return val_ + index;
  }
  counting_iterator &operator++() noexcept {
    ++val_;
    return *this;
  }
  counting_iterator operator++(int) noexcept {
    counting_iterator res{*this};
    ++(*this);
    return res;
  }
  counting_iterator &operator--() noexcept {
    --val_;
    return *this;
  }
  counting_iterator operator--(int) noexcept {
    counting_iterator res{*this};
    --(*this);
    return res;
  }
  friend counting_iterator operator+(counting_iterator const &it,
                                     difference_type const &offset) noexcept;
  friend counting_iterator operator+(difference_type const &offset,
                                     counting_iterator const &it) noexcept;
  friend counting_iterator operator-(counting_iterator const &it,
                                     difference_type const &offset) noexcept;
  friend difference_type operator-(counting_iterator const &a,
                                   counting_iterator const &b) noexcept;
  counting_iterator &operator+=(difference_type offset) noexcept {
    val_ += offset;
    return *this;
  }
  counting_iterator &operator-=(difference_type offset) noexcept {
    val_ -= offset;
    return *this;
  }
  friend bool operator==(counting_iterator const &a,
                         counting_iterator const &b) noexcept;
#if __cplusplus > 201703L
  friend std::strong_ordering operator<=>(counting_iterator const &a,
                                          counting_iterator const &b);
#else
  friend bool operator!=(counting_iterator const &a,
                         counting_iterator const &b) noexcept;
  friend bool operator<=(counting_iterator const &a,
                         counting_iterator const &b) noexcept;
  friend bool operator>=(counting_iterator const &a,
                         counting_iterator const &b) noexcept;
  friend bool operator<(counting_iterator const &a,
                        counting_iterator const &b) noexcept;
  friend bool operator>(counting_iterator const &a,
                        counting_iterator const &b) noexcept;
#endif
};

counting_iterator
operator+(counting_iterator const &it,
          counting_iterator::difference_type const &offset) noexcept {
  return counting_iterator{it.val_ + offset};
}
counting_iterator operator+(counting_iterator::difference_type const &offset,
                            counting_iterator const &it) noexcept {
  return counting_iterator{it.val_ + offset};
}
counting_iterator
operator-(counting_iterator const &it,
          counting_iterator::difference_type const &offset) noexcept {
  return counting_iterator{it.val_ - offset};
}
counting_iterator::difference_type
operator-(counting_iterator const &a, counting_iterator const &b) noexcept {
  return a.val_ - b.val_;
}
bool operator==(counting_iterator const &a,
                counting_iterator const &b) noexcept {
  return a.val_ == b.val_;
}
#if __cplusplus > 201703L
std::strong_ordering operator<=>(counting_iterator const &a,
                                 counting_iterator const &b) {
  return a.val_ <=> b.val_;
}
#else
bool operator!=(counting_iterator const &a,
                counting_iterator const &b) noexcept {
  return a.val_ != b.val_;
}
bool operator<=(counting_iterator const &a,
                counting_iterator const &b) noexcept {
  return a.val_ <= b.val_;
}
bool operator>=(counting_iterator const &a,
                counting_iterator const &b) noexcept {
  return a.val_ >= b.val_;
}
bool operator<(counting_iterator const &a,
               counting_iterator const &b) noexcept {
  return a.val_ < b.val_;
}
bool operator>(counting_iterator const &a,
               counting_iterator const &b) noexcept {
  return a.val_ > b.val_;
}
#endif

int main() {
    auto res = std::transform_reduce(
                std::execution::par, 
                counting_iterator(0), counting_iterator(10), 
                0L, 
                std::plus<>(), 
                [](const std::ptrdiff_t& i) { return i * i; });

    std::cout << res << std::endl;
}

編輯:我在 class 上工作,使其也可以與 C++17 一起使用。 現在它還顯式地定義了std::random_access_iterator_tag 我仍然沒有使用該執行策略進行任何並行計算,無論是使用迭代器還是使用向量,所以我不知道 class 本身是否會抑制並行執行。

經過一些按摩和實驗,我確認雙向迭代器,基於上面 Paul 的示例,已經工作:

class counting_iterator {
public:
    using iterator_category = std::bidirectional_iterator_tag;
    using difference_type = std::ptrdiff_t;
    using value_type = std::ptrdiff_t;
private:
    value_type val_;
public:
    counting_iterator() : val_(0) {}
    explicit counting_iterator(value_type init) : val_(init) {}

    value_type operator*() noexcept { return val_; }
    const value_type& operator*() const noexcept { return val_; }

    counting_iterator& operator++() noexcept { ++val_; return *this; }
    counting_iterator operator++(int) noexcept { counting_iterator res{ *this }; ++(*this); return res; }

    counting_iterator& operator--() noexcept { --val_; return *this; }
    counting_iterator operator--(int) noexcept { counting_iterator res{ *this }; --(*this); return res; }

    value_type operator[](difference_type index) noexcept { return val_ + index; }

    counting_iterator& operator+=(difference_type offset) noexcept { val_ += offset; return *this; }
    counting_iterator& operator-=(difference_type offset) noexcept { val_ -= offset; return *this; }

    counting_iterator operator+(difference_type offset) const noexcept { return counting_iterator{ *this } += offset; };
    /*counting_iterator& operator+(difference_type offset) noexcept { return operator+=(offset); }*/

    counting_iterator operator-(difference_type offset) const noexcept { return counting_iterator{ *this } -= offset; };

    /*counting_iterator& operator-(difference_type offset) noexcept { return operator-=(offset); }*/

    difference_type operator-(counting_iterator const& other) noexcept { return val_ - other.val_; }

    bool operator<(counting_iterator const& b) const noexcept { return val_ < b.val_; }
    bool operator==(counting_iterator const& b) const noexcept { return val_ == b.val_; }
    bool operator!=(counting_iterator const& b) const noexcept { return !operator==(b); }

    std::strong_ordering operator<=>(counting_iterator const& b) const noexcept { return val_ <=> b.val_; }
};

盡管std::transform_reduceiterator_category = std::random_access_iterator_tag並行工作,但我無法使其工作,我相信這是性能下降的原因。

UPD:在上面的代碼中,注釋行使 MS 編譯器選擇它們而不是復制版本替代方案,如果迭代器被標記為 random_access_category_tag,則會在並行執行期間造成嚴重破壞。

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM