Shell 腳本將 json object 分配給變量進行迭代

Question

DATA="$(curl "https://www.alphavantage.co/query?function=SYMBOL_SEARCH&keywords=BA&apikey=demo" | jq '.bestMatches' | jq '.[] | ."1. symbol"')"

我想遍歷 DATA 變量，理想情況下它是一個數組。 我想在這里做的是兩方面的。

1. 我需要一種方法來 select 所有“matchScore”大於 0.5 的記錄的“1.symbol”屬性。 這對我來說是一件有問題的事情，因為 matchScore 包含一個字符串，而不是一個數字。
2. 我想將選定的“1. Symbol”屬性存儲在一個變量中，稍后我可以對其進行迭代以執行更多操作。

{
  "bestMatches": [
    {
      "1. symbol": "BA",
      "2. name": "The Boeing Company",
      "3. type": "Equity",
      "4. region": "United States",
      "5. marketOpen": "09:30",
      "6. marketClose": "16:00",
      "7. timezone": "UTC-05",
      "8. currency": "USD",
      "9. matchScore": "1.0000"
    },
    {
      "1. symbol": "BAC",
      "2. name": "Bank of America Corporation",
      "3. type": "Equity",
      "4. region": "United States",
      "5. marketOpen": "09:30",
      "6. marketClose": "16:00",
      "7. timezone": "UTC-05",
      "8. currency": "USD",
      "9. matchScore": "0.8000"
    },
    {
      "1. symbol": "BABA",
      "2. name": "Alibaba Group Holding Limited",
      "3. type": "Equity",
      "4. region": "United States",
      "5. marketOpen": "09:30",
      "6. marketClose": "16:00",
      "7. timezone": "UTC-05",
      "8. currency": "USD",
      "9. matchScore": "0.6667"
    },
    {
      "1. symbol": "GOLD",
      "2. name": "Barrick Gold Corporation",
      "3. type": "Equity",
      "4. region": "United States",
      "5. marketOpen": "09:30",
      "6. marketClose": "16:00",
      "7. timezone": "UTC-05",
      "8. currency": "USD",
      "9. matchScore": "0.5714"
    },
    {
      "1. symbol": "BIDU",
      "2. name": "Baidu Inc.",
      "3. type": "Equity",
      "4. region": "United States",
      "5. marketOpen": "09:30",
      "6. marketClose": "16:00",
      "7. timezone": "UTC-05",
      "8. currency": "USD",
      "9. matchScore": "0.5000"
    },
    {
      "1. symbol": "BAYRY",
      "2. name": "Bayer Aktiengesellschaft",
      "3. type": "Equity",
      "4. region": "United States",
      "5. marketOpen": "09:30",
      "6. marketClose": "16:00",
      "7. timezone": "UTC-05",
      "8. currency": "USD",
      "9. matchScore": "0.4000"
    },
    {
      "1. symbol": "BLDP",
      "2. name": "Ballard Power Systems Inc.",
      "3. type": "Equity",
      "4. region": "United States",
      "5. marketOpen": "09:30",
      "6. marketClose": "16:00",
      "7. timezone": "UTC-05",
      "8. currency": "USD",
      "9. matchScore": "0.3333"
    },
    {
      "1. symbol": "BHC",
      "2. name": "Bausch Health Companies Inc.",
      "3. type": "Equity",
      "4. region": "United States",
      "5. marketOpen": "09:30",
      "6. marketClose": "16:00",
      "7. timezone": "UTC-05",
      "8. currency": "USD",
      "9. matchScore": "0.3333"
    },
    {
      "1. symbol": "BK",
      "2. name": "The Bank of New York Mellon Corporation",
      "3. type": "Equity",
      "4. region": "United States",
      "5. marketOpen": "09:30",
      "6. marketClose": "16:00",
      "7. timezone": "UTC-05",
      "8. currency": "USD",
      "9. matchScore": "0.1538"
    }
  ]
}

上面是我得到的json object。

Answer 1

使用 tonumber 等將字段值從 integer 轉換為數字：

readarray data <<< "$(jq -r '.bestMatches[] | select(."9. matchScore" | tonumber > 0.5) | ."1. symbol"' jq)"

將jq命令的output重定向到readarray中創建數組。