如何使用 python 比較具有字典列表的兩個字典元素

Question

我正在嘗試比較兩個字典，其中包含作為字典元素列表的值。 如果字典相同，我的結果應該返回 True 或 False，否則返回 False，如果字典不同，我想獲得不同的值。以下是我嘗試過的代碼，我嘗試參考更多 stackoverflow 答案但我無法從他們那里得到。因此發布了一個新問題。我也是 python 的新手。

以下是我的示例數據

dict_a = {
    "hello@gmail.com": [
        {
            "casecode": "143-10",
            "ServiceName": "ec2",
            "ID/TypeOfService": "instance/i-030e7c1f50e06a500",
            "ipaddress": "172.21.156.26",
            "intance_name": "test-demo",
            "TechnicalOwner": "hello@gmail.com",
            "Owner": "Empty"
        },
        {
            "casecode": "243-11",
            "ServiceName": "s3",
            "ID/TypeOfService": "s3-for-logs",
            "ipaddress": "Empty",
            "intance_name": "Empty",
            "TechnicalOwner": "hello@gmail.com",
            "Owner": "Empty"
        }
    ]
}


dict_b = {
    "hello@gmail.com": [
        {
            "casecode": "143-10",
            "ServiceName": "ec2",
            "ID/TypeOfService": "instance/i-030e7c1f50e06a500",
            "ipaddress": "172.21.156.26",
            "intance_name": "test-demo",
            "TechnicalOwner": "hello@gmail.com",
            "Owner": "Empty"
        },
        {
            "casecode": "243-10",
            "ServiceName": "s3",
            "ID/TypeOfService": "s3-for-logs",
            "ipaddress": "Empty",
            "intance_name": "Empty",
            "TechnicalOwner": "hello@gmail.com",
            "Owner": "Empty"
        }
    ]
}

def get_lists(dict_a,dict_b):
    for type_, case_code_info in dict_a.items():
        dict_b_case_code = dict_a[type_]
        if type_ in dict_b.keys():
            for item_a in case_code_info:
                for item_b in dict_b_case_code:
                    value_b = item_b.values()
                    for (key_a,value_a) in item_a.items():
                        if value_a == value_b:
                            return True
                        else:
                            return False

Answer 1

same = True

for (x,x_nest),(y,y_nest) in zip(dict_a.items(),dict_b.items()):
    for x_nested, y_nested in zip(x_nest, y_nest):
        for(x_key,x_value),(y_key,y_value) in zip(x_nested.items(),y_nested.items()):
            if x_value != y_value:
                print(x_key,x_value)
                print(y_key,y_value,'\n')
                same = False
            else:
                pass
print(same)

>>> casecode 243-11
    casecode 243-10 

    False

如果鍵未排序

same = True

for (x,x_nest),(y,y_nest) in zip(dict_a.items(),dict_b.items()):
    for x_nested, y_nested in zip(x_nest, y_nest):
        for x_key,x_value in x_nested.items():
            for y_key,y_value in y_nested.items():
                if y_key == x_key:
                    if x_value != y_value:
                        print(x_key,x_value)
                        print(y_key,y_value,'\n')
                        same = False
                    else:
                        pass
print(same)

Answer 2

您可以安裝一個名為 deepdiff 的模塊

pip 安裝 deepdiff

您想要的代碼如下所示：

dict_1 = {
    "hello@gmail.com": [
        {
            "casecode": "143-10",
            "ServiceName": "ec2",
            "ID/TypeOfService": "instance/i-030e7c1f50e06a500",
            "ipaddress": "172.21.156.26",
            "intance_name": "test-demo",
            "TechnicalOwner": "hello@gmail.com",
            "Owner": "Empty"
        },
        {
            "casecode": "243-11",
            "ServiceName": "s3",
            "ID/TypeOfService": "s3-for-logs",
            "ipaddress": "Empty",
            "intance_name": "Empty",
            "TechnicalOwner": "hello@gmail.com",
            "Owner": "Empty"
        }
    ]
}


dict_2 = {
    "hello@gmail.com": [
        {
            "casecode": "143-10",
            "ServiceName": "ec2",
            "ID/TypeOfService": "instance/i-030e7c1f50e06a500",
            "ipaddress": "172.21.156.26",
            "intance_name": "test-demo",
            "TechnicalOwner": "hello@gmail.com",
            "Owner": "Empty"
        },
        {
            "casecode": "243-10",
            "ServiceName": "s3",
            "ID/TypeOfService": "s3-for-logs",
            "ipaddress": "Empty",
            "intance_name": "Empty",
            "TechnicalOwner": "hello@gmail.com",
            "Owner": "Empty"
        }
    ]
}
import deepdiff
import json

diff = deepdiff.DeepDiff(dict_1, dict_2)
print(json.dumps(diff, indent=4))

答案非常簡潔，有條理，而且速度很快。