為什么我在此 bash 代碼中有語法錯誤？

Question

a=0
b=0
numterms=0
echo -e -n "\nEnter a number for variable a: "
read a
echo ""
echo -e -n "\nEnter a number for variable b: "
read b
echo ""
echo -e -n "\nEnter a number for how many terms printed: "
read numterms
echo ""
n=1
numtermss=$(($numterms+1))
while [ $n -lt $numtermss ]
do
        sum=$(($a * $n + $b))
        n=$(($n + 1))
        echo $sum
        if [ $numterms -lt 0 ]
        then
                echo -e -n "Number needs to be postive."
                echo ""
        else
                echo -e -n "\nEnter another number for variable a: "
                read aa
                echo ""
                echo -e -n "n\Enther another number for variable b: "
                read bb
                echo ""
                echo -e -n "n\Enter another number for amount of terms: "
                read terms
                echo ""
                        aa=0
                        bb=0
                        terms=0
                        for i in "$@"
                        do
                        number=(head -1 "$i")
                        bb=$((bb+1))
                        aa=$((aa + number))
                        termss=$(($terms+1))
                        echo " The sum is $aa"
fi
done

我試圖讓 bash 代碼創建一個線性序列，其中用戶輸入變量 a、b 以及應該有多少項是 output。 U=a(n)+b 然后為相同的線性序列選擇其他變量和 output 的計數之和。

Answer 1

您在開頭缺少一個 shebang，結尾處的 for 循環中缺少一個分號，以及 done to 和 for 循環。 我還添加了一個正確的退出命令。

#!/bin/bash

a=0
b=0
numterms=0
echo -e -n "\nEnter a number for variable a: "
read a
echo ""
echo -e -n "\nEnter a number for variable b: "
read b
echo ""
echo -e -n "\nEnter a number for how many terms printed: "
read numterms
echo ""
n=1
numtermss=$(($numterms+1))
while [ $n -lt $numtermss ]
do
        sum=$(($a * $n + $b))
        n=$(($n + 1))
        echo $sum
        if [ $numterms -lt 0 ]
        then
                echo -e -n "Number needs to be postive."
                echo ""
        else
                echo -e -n "\nEnter another number for variable a: "
                read aa
                echo ""
                echo -e -n "n\Enther another number for variable b: "
                read bb
                echo ""
                echo -e -n "n\Enter another number for amount of terms: "
                read terms
                echo ""
                        aa=0
                        bb=0
                        terms=0
                        for i in "$@";
                        do
                        number=(head -1 "$i")
                        bb=$((bb+1))
                        aa=$((aa + number))
                        termss=$(($terms+1))
                        echo " The sum is $aa"
                done
fi
done
exit 0