以不帶 0 的間隔對數據進行分組

Question

我有下表：

+---------------------+--------+----------+
| MeasureInterval     | Car_id | Distance |
+---------------------+--------+----------+
| 2020-12-15 17:00:00 | 1      | 20       |
+---------------------+--------+----------+
| 2020-12-15 17:05:00 | 1      | 30       |
+---------------------+--------+----------+
| 2020-12-15 17:10:00 | 1      | 17       |
+---------------------+--------+----------+
| 2020-12-15 17:15:00 | 1      | 0        |
+---------------------+--------+----------+
| 2020-12-15 17:20:00 | 1      | 0        |
+---------------------+--------+----------+
| 2020-12-15 17:25:00 | 1      | 10       |
+---------------------+--------+----------+
| 2020-12-15 17:30:00 | 1      | 15       |
+---------------------+--------+----------+
| 2020-12-15 17:35:00 | 1      | 0        |
+---------------------+--------+----------+
| 2020-12-15 17:40:00 | 1      | 0        |
+---------------------+--------+----------+
| 2020-12-15 17:45:00 | 1      | 0        |
+---------------------+--------+----------+

我正在嘗試 select 汽車移動的連續間隔（忽略距離 = 0 的間隔），因此結果將類似於：

+---------------------+---------------------+--------+--------------+
|                     |                     |        |              |
| MeasureInterval_min | MeasureInterval_max | Car_id | Distance_sum |
+---------------------+---------------------+--------+--------------+
| 2020-12-15 17:00:00 | 2020-12-15 17:10:00 | 1      | 67           |
+---------------------+---------------------+--------+--------------+
| 2020-12-15 17:25:00 | 2020-12-15 17:30:00 | 1      | 25           |
+---------------------+---------------------+--------+--------------+ 

知道如何實現這一目標嗎？

Answer 1

這是一個差距和孤島問題。 島嶼是具有非零距離的相鄰記錄。

這是一種使用行號之間的差異來識別組的方法：

select 
    min(measureinterval) as measureinterval_min,
    max(measureinterval) as measureinterval_max,
    car_id,
    sum(distance) as distance
from (
    select t.*,
        row_number() over(partition by carid order by measureinterval) rn1,
        row_number() over(partition by carid, (distance = 0) order by measureinterval) rn2
    from mytable t
) t
where distance > 0
group by car_id, rn1 - rn2