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[英]Selenium how can i locate multiple (second,third,fourth,etc) elements with the same class name by class_name in python
[英]How can I find multiple usernames that have the same class name in Python with Selenium?
if type == 2:
for p in range(1, maxpages + 1):
link = url + str(p)
driver.get(link)
Users = driver.find_elements_by_class_name("link span h5 hv7 secondary")
print(Users[0].text)
print(Users[1].text)
print(Users[2].text)
我希望你能理解我想用上面的代碼做什么。
我正在嘗試查找具有 class 名稱的所有元素:link span h5 hv7 secondary(超過 100 個)
然后分別打印出來。
Nic 的回復錯誤:
User: <selenium.webdriver.remote.webelement.WebElement (session="39c90e31145c4cc21937f591facb1d2d", element="880b3920-08ae-443b-a7ad-621ffd988ce8")>
Age: <selenium.webdriver.remote.webelement.WebElement (session="39c90e31145c4cc21937f591facb1d2d", element="dc0297b0-f21f-4492-8be4-e14b5126d2bb")>
Traceback (most recent call last):
File "C:\Users\VENA2\PycharmProjects\pythonProject\main.py", line 85, in <module>
print(f"Text: {user_container.find_element_by_css_selector('div.f6.nowrap.truncate')}")
File "C:\Users\VENA2\PycharmProjects\pythonProject\venv\lib\site-packages\selenium\webdriver\remote\webelement.py", line 430, in find_element_by_css_selector
return self.find_element(by=By.CSS_SELECTOR, value=css_selector)
File "C:\Users\VENA2\PycharmProjects\pythonProject\venv\lib\site-packages\selenium\webdriver\remote\webelement.py", line 658, in find_element
return self._execute(Command.FIND_CHILD_ELEMENT,
File "C:\Users\VENA2\PycharmProjects\pythonProject\venv\lib\site-packages\selenium\webdriver\remote\webelement.py", line 633, in _execute
return self._parent.execute(command, params)
File "C:\Users\VENA2\PycharmProjects\pythonProject\venv\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 321, in execute
self.error_handler.check_response(response)
File "C:\Users\VENA2\PycharmProjects\pythonProject\venv\lib\site-packages\selenium\webdriver\remote\errorhandler.py", line 242, in check_response
raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector","selector":"div.f6.nowrap.truncate"}
(Session info: chrome=87.0.4280.88)
Process finished with exit code 1
class 屬性中的空格表示多個類,因此請使用“。” 而不是空格來表示多個類:
Users = driver.find_elements_by_class_name("link.span.h5.hv7.secondary")
您還可以使用 xpath 或 css 來匹配精確的 class 屬性值:
CSS:
Users = driver.find_elements_by_css_selector("[class='link span h5 hv7 secondary']")
Xpath:
Users = driver.find_elements_by_xpath("//*[@class='link span h5 hv7 secondary']")
使用帶空格的 class 示例:
from selenium import webdriver
from time import sleep
options = webdriver.ChromeOptions()
#options.headless = True
options.add_argument("--window-size=1920,1080")
options.add_argument("--headless")
options.add_argument("--disable-gpu")
options.add_argument(
"user-agent=Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/87.0.4280.88 Safari/537.36")
browser = webdriver.Chrome(options=options)
browser.get("https://www.instagram.com")
sleep(5)
#browser.refresh()
elem=browser.find_element_by_class_name('RP4i1.UVauz')
print(elem.get_attribute("outerHTML"))
browser.get_screenshot_as_file(f"screenshot.png")
Output:
<img class="RP4i1 UVauz" src="/static/images/homepage/screenshot1.jpg/d6bf0c928b5a.jpg" alt="">
只需遍歷它們。
for user in Users:
print(user.text)
使用find_elements_by_class_name
您必須將每個空格替換為“。” 正如@PDHide 所述。 此選擇僅限於類,我建議將css_selector
與find_elements_by_css_selector
一起使用。 這允許您混合 ID、classNames、tagName..
您需要輸入的值與 css 查詢相同。 首先 class 必須以“.”開頭並且同一級別的任何類都必須用“。”分隔。 以及。 如果它們是多個級別(子級),則用空格隔開,后跟“.”。
更多關於帶有 selenium 的 css_selector 的信息在 這里
有關如何在此處建立查詢值的更多信息
完成查詢后,您可以使用 for 循環通過列表進行交互:
Users = driver.find_elements_by_css_selector("yourCssSelectorValue")
for user in Users:
print(user.text)
從提供的屏幕截圖中,這里有一個獲取用戶/年齡/文本的解決方案。
首先獲取父元素:
user_containers = driver.find_elements_by_css_selector('div.relative.flex-auto.mw-100')
然后獲取每個 Childs 並打印結果:
for user_container in user_containers:
print(f"User: {user_container.find_element_by_css_selector('.link.span.h5.hv7.secondary').text}")
print(f"Age: {user_container.find_element_by_css_selector('span.f6.fw7.silver').text}")
print(f"Text: {user_container.find_element_by_css_selector('div.f6.nowrap.truncate').text}")
這是一種方式,但會有很多閱讀。
另一種解決方案,您也可以通過這種方式獲取所有孩子:
users = driver.find_element_by_css_selector('.link.span.h5.hv7.secondary')
age = driver.find_element_by_css_selector('span.f6.fw7.silver')
text = driver.find_element_by_css_selector('div.f6.nowrap.truncate')
然后 zip 列表並打印每個結果:
for values in zip(users, age, text):
print(f"Users: {values[0].text}")
print(f"Age: {values[1].text}")
print(f"Text: {values[2].text}")
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