MySQL 多個表中多行的總和

Question

我試圖從 2 個不同的表中獲取多行的總和，但結果以某種方式返回了多行。

我需要獲取 quotation_item_amount（按 quotation_id 分組）和 invoice_item_amount（按 invoice_id 分組）的總和，如果我查詢未付報價，我需要獲取 WHERE SUM(invoice) < SUM(quotation)

所以這是我的示例表

table client_project_id
+-------------------+-----------+----------------------+
| client_project_id | client_id | client_project_title |
+-------------------+-----------+----------------------+
|         23        |     5     |        Project 1     |
|         17        |     9     |        Project 2     |
|         54        |     7     |        Project 3     |
+-------------------+-----------+----------------------+

table quotation
+--------------+-------------------+------------------+
| quotation_id | client_project_id | quotation_number |
+--------------+-------------------+------------------+
|       1      |          23       |   Q/01/2020/001  |
|       2      |          17       |   Q/01/2020/002  |
|       3      |          54       |   Q/01/2020/003  |
+--------------+-------------------+------------------+

table quotation_item
+-------------------+--------------+-----------------------+
| quotation_item_id | quotation_id | quotation_item_amount |
+-------------------+--------------+-----------------------+
|         1         |     1        |          500          |
|         2         |     1        |          700          |
|         3         |     1        |          600          |
|         4         |     2        |          200          |
|         5         |     2        |          150          |
|         6         |     3        |          900          |
+-------------------+--------------+-----------------------+

table invoice
+--------------+-------------------+------------------+
|  invoice_id  | client_project_id |  invoice_number  |
+--------------+-------------------+------------------+
|       1      |          23       |   I/01/2020/001  |
|       2      |          17       |   I/01/2020/002  |
|       3      |          54       |   I/01/2020/003  |
+--------------+-------------------+------------------+

table invoice_item
+-------------------+--------------+-----------------------+
|  invoice_item_id  |  invoice_id  |  invoice_item_amount  |
+-------------------+--------------+-----------------------+
|         1         |     1        |          500          |
|         2         |     1        |          700          |
|         3         |     1        |          600          |
|         4         |     2        |          200          |
|         5         |     2        |          150          |
|         6         |     3        |          900          |
+-------------------+--------------+-----------------------+

我需要得到的結果是：

1. quotation_item_amount 的 SUM 和 invoice_item_amount 的 SUM PER client_project_id
2. 查詢 WHERE SUM(invoice) < SUM(quotation)

這是我最近的查詢嘗試

SELECT 
    SUM(quotation_item.quotation_item_amount) as quot_amt, 
    SUM(invoice_item.invoice_item_amount) as inv_amt,
    data_client_project.client_project_id,
    data_client.client_name

FROM data_client_project a
LEFT JOIN quotation b ON a.client_project_id = b.client_project_id
LEFT JOIN data_client d ON a.client_id = d.client_id
LEFT JOIN invoice i ON a.client_project_id = i.client_project_id
JOIN (
        SELECT quotation_id, 
            SUM(c.quotation_item_amount) as quot_amt
        FROM quotation_item c 
        GROUP BY c.quotation_id
      ) quotitem
        ON b.quotation_id = quotitem.quotation_id
        JOIN (
            SELECT invoice_id, 
                SUM(e.invoice_item_price) as inv_amt
            FROM invoice_item e
            GROUP BY e.invoice_id
        ) invitem
        ON i.invoice_id = invitem.invoice_id

但是，這會導致 quotation_item_amount 和 invoice_item_amount 的多個重復行。

已嘗試使用 UNION / UNION ALL 和其他幾個不起作用的查詢。 謝謝你的所有建議。

Answer 1

看起來您正在嘗試同時沿兩個不同的維度進行聚合。 解決方案是沿每個維度進行預聚合：

SELECT *
FROM data_client_project cp LEFT JOIN
     (SELECT q.client_project_id,
             SUM(qi.quotation_item_amount * qi.quotation_item_qty) as quot_amt
      FROM quotation q JOIN
           quotation_item qi
           ON qi.quotation_id = q.quotation_id
      GROUP BY q.client_project_id
     ) q
     USING (client_project_id) LEFT JOIN
     (SELECT i.client_project_id,
             SUM(invoice_item_price) as inv_amt
      FROM invoice i JOIN
           invoice_item ii
           ON i.invoice_id = ii.invoice_id
      GROUP BY i.client_project_id
     ) i
     USING (client_project_id);

關於您的風格的兩個注意事項。

首先，您使用任意字母作為表別名。 如果您添加新表、刪除表或重新排列名稱，這會使查詢很難遵循並且變得很尷尬。 對表格使用縮寫。 更容易遵循。

其次，我真的不推薦SELECT *用於此類查詢。 但是，您可以通過將ON替換為USING來避免重復的列。

Answer 2

我可能遺漏了一些東西，但您的表描述不包括data_client或data_client_project的示例根據您的示例，我希望您的行擴展來自前 3 個連接。

確保下面首先為您提供所需的數據列表，然后嘗試加入計算：

SELECT *
    FROM data_client_project a
    LEFT JOIN quotation b ON a.client_project_id = b.client_project_id
    LEFT JOIN data_client d ON a.client_id = d.client_id
    LEFT JOIN invoice i ON a.client_project_id = i.client_project_id;
#you may want to append the above with a limit 100 for testing.

Answer 3

如果您在主查詢中有重復的行，則為 obatin 添加不同的行，並且添加用於通過 quotitem.quot_amt < invitem.inv_amt 過濾結果的條件

    SELECT distinct a.*, b.*, d.*, i.*  
    FROM data_client_project a
    LEFT JOIN quotation b ON a.client_project_id = b.client_project_id
    LEFT JOIN data_client d ON a.client_id = d.client_id
    LEFT JOIN invoice i ON a.client_project_id = i.client_project_id
    JOIN (
            SELECT quotation_id, 
                SUM(c.quotation_item_amount * c.quotation_item_qty) as quot_amt
            FROM quotation_item c 
            GROUP BY c.quotation_id
          ) quotitem  ON b.quotation_id = quotitem.quotation_id
    JOIN (
            SELECT invoice_id, 
                SUM(e.invoice_item_price) as inv_amt
            FROM invoice_item e
            GROUP BY e.invoice_id
            ) invitem  ON i.invoice_id = invitem.invoice_id
    WHERE quotitem.quot_amt < invitem.inv_amt