將不同數組中的值推送到不同的鍵

Question

我有2個這樣的數組：

let payrollname = [{"code": "a1", "name": "Loan A"}, {"code": "a2", "name": "Loan B"}, {"code": "a3", "name": "Loan C"}, {"code": "a4", "name": "Loan D"}, {"code": "a5", "name": "Loan E"}]

和

let payrollbalance = [{"a1": 0, "a2": 100000, "a3": 500000, "a4": 300000, "a5": 45900}]

我如何將值從payrollbalance推送到payrollname ？

我的意思是像這樣推送，來自payrollbalance.a4的值，這意味着300000推送到payrollname.code == a4

我希望最終結果可以類似：

let result = `[{"code": "a1", "name": "Loan A", "values": 0}, {"code": "a2", "name": "Loan B", , "values": 100000}, {"code": "a3", "name": "Loan C", "values": 500000}, {"code": "a4", "name": "Loan D", "values": 300000}, {"code": "a5", "name": "Loan E",  "values": 45900}]`

任何幫助都會得到幫助，我已經搞砸了一整天。

提前致謝

Answer 1

使用Array.map()並添加帶有 payrollbalance[0] 值的values鍵，並通過[]指示 json 鍵用於動態。

 let payrollname = [{"code": "a1", "name": "Loan A"}, {"code": "a2", "name": "Loan B"}, {"code": "a3", "name": "Loan C"}, {"code": "a4", "name": "Loan D"}, {"code": "a5", "name": "Loan E"}] let payrollbalance = [{"a1": 0, "a2": 100000, "a3": 500000, "a4": 300000, "a5": 45900}] let result = payrollname.map(item => ({...item, values: payrollbalance[0][item.code] })); console.log(result);

Answer 2

做一個數組搜索，找到索引並在之后更改它

 let payrollname = [{"code": "a1", "name": "Loan A"}, {"code": "a2", "name": "Loan B"}, {"code": "a3", "name": "Loan C"}, {"code": "a4", "name": "Loan D"}, {"code": "a5", "name": "Loan E"}] let payrollbalance = [{"a1": 0, "a2": 100000, "a3": 500000, "a4": 300000, "a5": 45900}] var result = []; let pblance = payrollbalance[0] for(let p in pblance) { let index = payrollname.findIndex(el => el.code==p) let pname = payrollname[index] pname.values = pblance[p]; result.push(pname) } console.log(result);

Answer 3

此代碼將起作用！

 let payrollname = [{"code": "a1", "name": "Loan A"}, {"code": "a2", "name": "Loan B"}, {"code": "a3", "name": "Loan C"}, {"code": "a4", "name": "Loan D"}, {"code": "a5", "name": "Loan E"}] let payrollbalance = [{"a1": 0, "a2": 100000, "a3": 500000, "a4": 300000, "a5": 45900}] let result = [] let i = 0 payrollname.forEach(element => { let value = payrollbalance[0][element.code] element.values = value; result[i] = element i=i+1 }); console.log(result)