如何檢查對象的值是否與 Angular 中數組列表中的任何值匹配

Question

我有這樣的腳本：

let arrlist = ['Aple','Banana', 'Carrot', 'Onion'];

data = this.tabledata.filter(d=> {
      return Object.keys(d).some(key => {  
        if(searchTerm) {
          return String(d[key]).toLowerCase().includes(searchTerm.toLowerCase());
        } else {
          list.map(r => {return String(d[key]).toLowerCase().includes(r)}); //error
        }
      });
    });

我想從this.tabledata中過濾與列表匹配或包含arrlist的數據。 我應該怎么辦？ 請幫我

這是this.tabledata的數組對象：

[ {id: 1, name: "Jake", things: "Aple"}
{id: 2, name: "Anwar", things: "Carrot"}
{id: 3, name: "Lane", things: "Aple"}
{id: 4, name: "Curt", things: "Banana"}
{id: 5, name: "Pety", things: "Carrot"}
{id: 6, name: "Hary", things: "Aple"}
{id: 7, name: "Clara", things: "Aple"} ]

Answer 1

我有這樣的腳本：

let arrlist = ['Aple','Banana', 'Carrot', 'Onion'];

data = this.tabledata.filter(d=> {
      return Object.keys(d).some(key => {  
        if(searchTerm) {
          return String(d[key]).toLowerCase().includes(searchTerm.toLowerCase());
        } else {
          list.map(r => {return String(d[key]).toLowerCase().includes(r)}); //error
        }
      });
    });

我想從this.tabledata中過濾與列表匹配或包含arrlist的數據。 我應該怎么辦？ 請幫我

這是this.tabledata的數組對象：

[ {id: 1, name: "Jake", things: "Aple"}
{id: 2, name: "Anwar", things: "Carrot"}
{id: 3, name: "Lane", things: "Aple"}
{id: 4, name: "Curt", things: "Banana"}
{id: 5, name: "Pety", things: "Carrot"}
{id: 6, name: "Hary", things: "Aple"}
{id: 7, name: "Clara", things: "Aple"} ]

Answer 2

我有這樣的腳本：

let arrlist = ['Aple','Banana', 'Carrot', 'Onion'];

data = this.tabledata.filter(d=> {
      return Object.keys(d).some(key => {  
        if(searchTerm) {
          return String(d[key]).toLowerCase().includes(searchTerm.toLowerCase());
        } else {
          list.map(r => {return String(d[key]).toLowerCase().includes(r)}); //error
        }
      });
    });

我想從this.tabledata中過濾與列表匹配或包含arrlist的數據。 我應該怎么辦？ 請幫我

這是this.tabledata的數組對象：

[ {id: 1, name: "Jake", things: "Aple"}
{id: 2, name: "Anwar", things: "Carrot"}
{id: 3, name: "Lane", things: "Aple"}
{id: 4, name: "Curt", things: "Banana"}
{id: 5, name: "Pety", things: "Carrot"}
{id: 6, name: "Hary", things: "Aple"}
{id: 7, name: "Clara", things: "Aple"} ]

Answer 3

我有這樣的腳本：

let arrlist = ['Aple','Banana', 'Carrot', 'Onion'];

data = this.tabledata.filter(d=> {
      return Object.keys(d).some(key => {  
        if(searchTerm) {
          return String(d[key]).toLowerCase().includes(searchTerm.toLowerCase());
        } else {
          list.map(r => {return String(d[key]).toLowerCase().includes(r)}); //error
        }
      });
    });

我想從this.tabledata中過濾與列表匹配或包含arrlist的數據。 我應該怎么辦？ 請幫我

這是this.tabledata的數組對象：

[ {id: 1, name: "Jake", things: "Aple"}
{id: 2, name: "Anwar", things: "Carrot"}
{id: 3, name: "Lane", things: "Aple"}
{id: 4, name: "Curt", things: "Banana"}
{id: 5, name: "Pety", things: "Carrot"}
{id: 6, name: "Hary", things: "Aple"}
{id: 7, name: "Clara", things: "Aple"} ]