如何使用 BeautifulSoup 從“a”元素中提取文本？

Question

我正在嘗試從使用 beautifulsoup 獲得的“a”html 元素中獲取文本。 我可以打印整個東西，我想找到的東西就在那里：

-1
<a href="/manga/tensei-shitara-slime-datta-ken-fuse">Tensei Shitara Slime Datta Ken Manga</a>
-1

但是當我想更具體並從中獲取文本時，它會給我這個錯誤：

  File "C:\python\manga\manga.py", line 15, in <module>
    print(title.text)
AttributeError: 'int' object has no attribute 'text'

這是我正在運行的代碼：

import requests
from bs4 import BeautifulSoup

URL = 'https://mangapark.net/manga/tensei-shitara-slime-datta-ken-fuse'
page = requests.get(URL)
soup = BeautifulSoup(page.content, 'html.parser')

results = soup.find('section', class_='manga')

manga_title = soup.find('div', class_='pb-1 mb-2 line-b-f hd')


for m_title in manga_title:
    title = m_title.find('a')
    print(title.text)

我已經搜索了我的問題，但找不到有用的東西。

Answer 1

美麗的湯在搜索中沒有找到值時返回 -1 這在 python 中不是很常見的方式來顯示不存在值，但它是其他語言的常見方式。

import requests
from bs4 import BeautifulSoup

URL = 'https://mangapark.net/manga/tensei-shitara-slime-datta-ken-fuse'
page = requests.get(URL)
soup = BeautifulSoup(page.content, 'html.parser')

results = soup.find('section', class_='manga')

manga_title = soup.find('div', class_='pb-1 mb-2 line-b-f hd')

for m_title in manga_title.children:
    title = m_title.find('a')

    # Beautiful soup returns -1 as a value when it doesn't find something in a search
    # This isn't a very pythonic way to show non existent values but it is a common one
    if title != -1: 
        print(title.text)

Output

Tensei Shitara Slime Datta Ken Manga