[英]write a python program to reverse the given numbers
輸入=12345 輸出=54321
編寫數字反轉的程序
n=int(input("Enter number :"))
rev=0
while(n>0):
dig = n%10
rev=rev*10+dig
n=n//10
print("The reverse of the number:" ,rev)
有人可以解釋為什么這個打印 54321
您可以在 python 中迭代一個字符串,並且您將按每個字符進行迭代
你有 go:
a = input("Enter : ")
x = [num for num in a] # Getting the individual digits
b = reversed(x) # reversed() is a built in function
print("".join(b))
這要簡單得多
inp = input("Enter the number")
list1 = [numbers for numbers in inp]
list2 = [reversed_numbers for reversed_numbers in list1[::-1]]
print("".join(list2))
這應該有效
number = int(input("Enter a number: "))
rev = ''
while number > 0:
last_digit = number % 10 #The remainder when it's divided by 10 will always be the last digit
rev = rev + str(last_digit)
number = number // 10
print("Reversed : ", rev)
讓 n = 12345,其中 12345 是給定的輸入。
rev = 0
Now in the first iteration of the while loop n > 0
dig = remainder of n divided by 10, So it is = 5
rev = rev(0) * 10 + dig(5) = 5
n = n // 10 = 1234
在第二次迭代中,n = 1234 > 0
rev = 5
dig = remainder of n divided by 10, So it is = 4
rev = rev(5) * 10 + dig(4) = 54
n = n // 10 = 123
在第三次迭代中 n = 123 > 0
rev = 54
dig = remainder of n divided by 10, So it is = 3
rev = rev(54) * 10 + dig(3) = 543
n = n // 10 = 12
在第四次迭代中 n = 12 > 0
rev = 543
dig = remainder of n divided by 10, So it is = 2
rev = rev(543) * 10 + dig(2) = 5432
n = n // 10 = 1
在第五次迭代中,n = 1 > 0
rev = 5432
dig = remainder of n divided by 10, So it is = 1
rev = rev(5432) * 10 + dig(1) = 54321
n = n // 10 = 0
現在在 while 循環的第六次迭代中 n = 0 所以它不大於 0 所以循環會中斷並且你得到 rev = 54321
其實很簡單
第一次迭代
第二次迭代
第三次迭代
...
但是,有更簡單的方法可以做到這一點,例如。
如果您的輸入是字符串,那么您只需要反轉它
input = "12345"
output = input[::-1]
如果輸入是數字(int,float),則必須將其轉換為字符串
input = 12345
output = str(input)[::-1]
並轉換回來
int(output)
請參閱其他答案以獲得很好的解釋。 在這里,我為原始問題添加了 2 個更簡單的解決方案 - 如何反轉數字:
# For example, 12345:
num = input("Enter number: ")
# fastest and shortest:
rev = num[::-1]
# or (slower and longer)
rev = "".join(reversed(num))
print(f"The reverse of the number: {rev}")
# The reverse of the number: 54321
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