ORACLE SQL 的合並/更新查詢

Question

我有兩個不同的表，table1 和 table2，如下所示

表格1

LA_ID	地址	城市	STATE
572	A1	C1	S1
300	A1	C1	S1
978	A1	C1	S1
082	A2	C2	S2
026	A2	C2	S2
093	A2	C2	S2

表2

LA_ID
572
572
300
300
978
978
978
978
082
082
082
026
026
093

我想更新 table2 LA_ID 看起來像

LA_ID
572
572
572
572
572
572
572
572
082
082
082
082
082
082

基本上將table2的LA_ID更新為table1的LA_ID，其中ADDRESS、CITY和state是相同的。

我試過這個

SET LA_ID = (SELECT new_LA_ID from (
(Select min(LA_ID) over
(partition by ADDRESS, city, state) as new_LA_ID,
LA_ID old_LA_ID
from table2 )) src
where src.old_LA_ID = tgt.LA_ID )
where tgt.LA_ID in (Select LA_ID old_LA_ID
from table2 
);

Answer 1

如果您願意只使用最小值或最大值，則可以簡單地使用update ：

update table_2 t2
    set la_id = (select min(t1.la_id)
                 from table_1 t1 join
                      table_1 t12
                      on t1.state = t12.state and t1.city = t12.city and t1.address = t12.address
                 where t12.la_id = t2.la_id
                )
    where la_id <> (select min(t1.la_id)
                    from table_1 t1 join
                         table_1 t12
                         on t1.state = t12.state and t1.city = t12.city and t1.address = t12.address
                    where t12.la_id = t2.la_id
                   );

我不確定在有重復項時如何為所需的特定 ID 選擇572和082 。 這將選擇300和026 。