如何使用 puppeteer 從節點 js 中接收的數據中刪除換行符

Question

我需要以下代碼的幫助。 如何刪除 rawTxt output 中的所有換行符 \n？ rawTxt 的當前 output 是 rawTxt: '\n\n\n\n\n\n\n\nKangol Men, Women Washed Bucket Hat\n\n\n\n\n\n\n'

我試過 .replace(/\n/g) 和 .replace([\s\S]) 但沒有運氣。 今天一直在尋找，但沒有運氣:(

const puppeteer = require('puppeteer');

async function scrapeProduct(url) {
    const browser = await puppeteer.launch();
    const page = await browser.newPage();
    await page.goto(url);

    const [el] = await page.$x('//*[@id="landingImage"]');
    const src = await el.getProperty('src');
    const srcTxt = await src.jsonValue();

    const [el2] = await page.$x('//*[@id="productTitle"]'.replace(/\n/g, ''));
    const txt = await el2.getProperty('textContent');
    const rawTxt = await txt.jsonValue();

    console.log({srcTxt, rawTxt});

    browser.close();
}

scrapeProduct("https://www.amazon.com/Kangol-Mens-Washed-Cotton-Bucket/dp/B0758LZQW6/ref=sr_1_17?dchild=1&keywords=bucket+hat&qid=1609973810&sr=8-17");

// { srcTxt: 'https://images-na.ssl-images-amazon.com/images/I/41TF7rSBy8L._AC_UX342_.jpg', rawTxt: '\n\n\n\n\n\n\n\nKangol Men, Women Washed Bucket Hat\n\n\n\n\n\n\n' }

Answer 1

您可以嘗試以下代碼：

 const input = '\n\n\n\n\n\n\n\nKangol Men, Women Washed Bucket Hat\n\n\n\n\n\n\n'; console.log('initial input=', input); console.log('new input =', input.replaceAll('\n',''));

Answer 2

看來您只是放錯了替換電話。 嘗試這個：

    const [el2] = await page.$x('//*[@id="productTitle"]');
    const txt = await el2.getProperty('textContent');
    const rawTxt = (await txt.jsonValue()).replace(/\n/g, '');

或這個：

    const [el2] = await page.$x('//*[@id="productTitle"]');
    const txt = await el2.getProperty('textContent');
    const rawTxt = (await txt.jsonValue()).trim();

或者這個（ innerText通常更具可讀性並且空格更少）：

    const [el2] = await page.$x('//*[@id="productTitle"]');
    const txt = await el2.getProperty('innerText');
    const rawTxt = (await txt.jsonValue());