SQL select 多個 arrays 並填充一個表

Question

我正在嘗試使用來自同一個表的 2 個 select 查詢的結果填充 1 個表。 它不起作用，一個填充另一個只顯示一個結果.. 是否可以在一個 select 中執行此操作，因為我認為問題在於使用兩個 fetch assoc。

問題：如何獲得我創建的表中顯示的這兩個查詢的結果？

<table align="left" style="width: auto; min-width: 700px; margin-bottom:20px;" class="deftable">
<thead><tr>
<th colspan="4">Top 10 users</th>
</tr>
</thead>
<thead><tr>
<th colspan="2">Top 10 Richest users</th>
<th colspan="2">Top 10 Bananaslappers</th>
</tr>
</thead>
<thead>
<tr><th>Name</th>
<th>Bananas</th>
<th>Name</th>
<th>Total slapped</th>
</tr></thead><tbody>
<?php

    $stmt88 = $mysqli->prepare("SELECT naam,geld FROM `gebruikers` ORDER BY geld DESC LIMIT 10 ");
    $stmt88->execute();
    $result = $stmt88->get_result(); //only works when nd_mysli is set on the server!
    $stmt88->close();
     while ($rowrich = $result->fetch_assoc()) {
        
    $stmt89 = $mysqli->prepare("SELECT naam,user_amountslapped FROM `gebruikers` ORDER BY user_amountslapped DESC LIMIT 10 ");
    $stmt89->execute();
    $result2 = $stmt89->get_result(); //only works when nd_mysli is set on the server!
    $stmt89->close();
    while ($rowrich2 = $result2->fetch_assoc()) {
     
 ?>
 
<tr><td >
<a class="online" href="profile.php?username=<?= htmlspecialchars($rowrich['naam']) ?>"><b><?= htmlspecialchars($rowrich['naam']) ?></b></a></td>
<td>&#127820;<?= htmlspecialchars(number_format($rowrich['geld'],0,",",".")) ?></td>

<td >
<a class="online" href="profile.php?username=<?= htmlspecialchars($rowrich2['naam']) ?>"><b><?= htmlspecialchars($rowrich2['naam']) ?></b></a></td>
<td>&#127820;<?= htmlspecialchars(number_format($rowrich2['user_amountslapped'],0,",",".")) ?></td>
</tr>
</tbody>
<? } }?></table><br>

Answer 1

你不應該有嵌套循環，這是在兩個結果之間創建一個叉積，而不是並行處理它們。

您應該有一個從每個查詢中獲取一行的循環。

<?php

    $stmt88 = $mysqli->prepare("SELECT naam,geld FROM `gebruikers` ORDER BY geld DESC LIMIT 10 ");
    $stmt88->execute();
    $result = $stmt88->get_result(); //only works when nd_mysli is set on the server!
    $stmt88->close();
    $stmt89 = $mysqli->prepare("SELECT naam,user_amountslapped FROM `gebruikers` ORDER BY user_amountslapped DESC LIMIT 10 ");
    $stmt89->execute();
    $result2 = $stmt89->get_result(); //only works when nd_mysli is set on the server!
    $stmt89->close();
    while (($rowrich = $result->fetch_assoc()) && ($rowrich2 = $result2->fetch_assoc())) {
 ?>
<tr><td >
<a class="online" href="profile.php?username=<?= htmlspecialchars($rowrich['naam']) ?>"><b><?= htmlspecialchars($rowrich['naam']) ?></b></a></td>
<td>&#127820;<?= htmlspecialchars(number_format($rowrich['geld'],0,",",".")) ?></td>

<td >
<a class="online" href="profile.php?username=<?= htmlspecialchars($rowrich2['naam']) ?>"><b><?= htmlspecialchars($rowrich2['naam']) ?></b></a></td>
<td>&#127820;<?= htmlspecialchars(number_format($rowrich2['user_amountslapped'],0,",",".")) ?></td>
</tr>
</tbody>
<? } ?></table><br>

請注意，如果任一查詢返回的行數少於 10 行，則表將在較短的長度處停止。 如果您想要更長的長度，請使用|| 在while條件下，然后在輸出這些列之前檢查$rowrich或$rowrich2是否為空。