將多行電話數據合並為顯示開始和結束日期的單行的腳本

Question

對於下表，我想：

一世。 合並行，以便對於每種電話類型，將相同電話號碼的集合合並為具有單個開始日期和結束日期的唯一電話號碼

ii. 合並電話號碼的 START DATE 是集合的最早開始日期，合並電話號碼的 END DATE 是集合的 LATEST 結束日期

iii. 此外，我想確保當某些不同的電話號碼按時間順序夾在一組相同的電話號碼中（由紅色虛線箭頭表示）時，那些相同的電話號碼不會合並到一行中。 相反，它們被合並為單獨的集合。 這是因為按時間順序，它們現在是獨立的集合

到目前為止我使用的腳本滿足第一個和第二個要求，但不滿足第三個要求

SELECT CLAIMANT_ID, PHONE_TYPE, PHONE_NUMBER, 
Min(START_DATE), Max(END_DATE) KEEP (DENSE_RANK FIRST ORDER BY END_DATE DESC NULLS FIRST)
FROM ClaimantData
GROUP BY CLAIMANT_ID, PHONE_TYPE, PHONE_NUMBER

有誰知道是否有任何方法可以增強腳本（或具有完全不同的腳本）也可以滿足第三個要求？

預期結果如下：

插入的示例數據

CREATE TABLE CLAIMANTDATA (    
CLAIMANT_ID NUMBER(9) NOT NULL,
PHONE_TYPE VARCHAR2(50 BYTE) NOT NULL,
PHONE_NUMBER VARCHAR2(50 BYTE) NULL,
START_DATE DATE NOT NULL,
END_DATE DATE NULL
);

Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Primary',7653030303,to_date('12-JAN-12','DD-MON-RR'),to_date('23-JAN-12','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Primary',7653030303,to_date('09-JAN-12','DD-MON-RR'),to_date('12-JAN-12','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Primary',7653030303,to_date('01-JAN-12','DD-MON-RR'),to_date('09-JAN-12','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7651000001,to_date('09-MAR-11','DD-MON-RR'),to_date('01-JAN-12','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7651000001,to_date('22-FEB-11','DD-MON-RR'),to_date('09-MAR-11','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7651000001,to_date('19-AUG-10','DD-MON-RR'),to_date('22-FEB-11','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7651000001,to_date('16-AUG-10','DD-MON-RR'),to_date('19-AUG-10','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',2062009876,to_date('14-AUG-10','DD-MON-RR'),to_date('16-AUG-10','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7651000001,to_date('08-APR-10','DD-MON-RR'),to_date('14-AUG-10','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7651000001,to_date('06-APR-10','DD-MON-RR'),to_date('08-APR-10','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7651000001,to_date('08-JUL-09','DD-MON-RR'),to_date('06-APR-10','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7651000001,to_date('15-JAN-09','DD-MON-RR'),to_date('08-JUL-09','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7650880880,to_date('22-DEC-08','DD-MON-RR'),to_date('15-JAN-09','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7651000001,to_date('07-AUG-08','DD-MON-RR'),to_date('22-DEC-08','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7651000001,to_date('06-AUG-08','DD-MON-RR'),to_date('07-AUG-08','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7651000001,to_date('06-AUG-08','DD-MON-RR'),to_date('06-AUG-08','DD-MON-RR'));
Insert into CLAIMANTDATA (CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,START_DATE,END_DATE) values (504,'Alternate',7651000001,to_date('13-NOV-07','DD-MON-RR'),to_date('28-MAR-08','DD-MON-RR'));

Answer 1

這稱為孤島和間隙問題。

您可以使用解析 function 如下：

Select CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER,
        Min(start_date),
        Max(end_date)
  From
(Select t.*,
       Row_number() over (partition by CLAIMANT_ID, PHONE_TYPE order by start_date) as rn,
       Row_number() over (partition by CLAIMANT_ID, PHONE_TYPE, PHONE_NUMBER order by start_date) as rn_p
   From CLAIMANTDATA t) t
Group by CLAIMANT_ID,PHONE_TYPE,PHONE_NUMBER, rn-rn_p

Answer 2

在 Oracle 12.1 或更高版本中，解決此類間隙和孤島問題的最簡單方法是使用match_recognize子句。

select claimant_id, phone_type, phone_number, start_date, end_date
from   claimantdata
match_recognize (
  partition by claimant_id, phone_type
  order     by start_date
  measures  a.phone_number as phone_number,
            a.start_date as start_date, last(end_date) as end_date
  pattern   ( a b* )
  define    b as phone_number = a.phone_number and start_date = prev(end_date)
);